Po-216- -----------------> Pb-212
210 4 214 84 PO -------> 2 alpha + 86 RN
Th-230(alpha)Ra-226.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
By alpha decay polonium-214 is transformed in lead-210. Po-214--------------alpha--------------Pb-210
The isotope radon-198 will alpha decay to polonium-194 as shown here: 86198Rn => 24He + 84194Po The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
210 4 214 84 PO -------> 2 alpha + 86 RN
Th-230(alpha)Ra-226.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
By alpha decay polonium-214 is transformed in lead-210. Po-214--------------alpha--------------Pb-210
The equation for the alpha decay of radon-222 takes the following form. Radon-222 ----> He + Polonium. In an alpha decay, the atom loses 2 neutrons and 2 protons.
lithium
224
229Th-------alpha particle-----------225Ra
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
Polonium 210-----------alpha particles-----------Lead 206 Polonium 209-----------alpha particles-----------Lead 205 Polonium 208-----------alpha particles-----------Lead 204 Polonium 214-----------alpha particles-----------Lead 210 Polonium 218-----------alpha particles-----------Lead 214 (99,98 %) Polonium 218-----------beta particles------------Astatin 218 (o,o2 %) For other isotopes see the list at: http://en.wikipedia.org/wiki/Polonium#Isotopes