#include
int main()
{
int num[100];
printf("please input your numbers.enter any letter for the end\n");
int i=0,j=0,k=0;
while(scanf("%d",&num[i++]));
i--;
printf("you input %d numbers\n",i);
for(j=i-1;j>=0;j--){
for(k=0;k<=j;k++){
if(num[k]>num[k+1]){
int temp;
temp=num[k+1];
num[k+1]=num[k];
num[k]=temp;
}
}
}
for(j=0;j<=i-1;j++){
if(j%5)
printf("%d ",num[j]);
else{
printf("\n");
printf("%d ",num[j]);
}
}
return 0;
}
#include #include void main() { int a[100],i,j,k,n; clrscr(); printf("How many number you want to genarate:"): scanf(" %d", &n); printf("Enter the numbers:"): for(i=0;i
(sort '(3 2 1) #'
(sort '(3 2 1)#'<)
Writing a C program that uses dynamic memory allocation to sort names in ascending order is a typical computer science assignment. To write this program, you must be in UNIX.
To write a C++ program to display the student details using class and array of object.
public class BubbleSortAscendingOrderDemo { public static void main(String a[]) { //Numbers which need to be sorted int numbers[] = {23,5,23,1,7,12,3,34,0}; //Displaying the numbers before sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } System.out.println(); //Sorting in ascending order using bubble sort bubbleSortInAscendingOrder(numbers); //Displaying the numbers after sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } }
No, "Hello world" is typically the first program assignment in introductory computer programming classes as it is trivial to write and almost useless.
Use a looping structure. The first step initialises a loop control variable, n, to zero. You then begin the loop by processing the nth element from the array (the process may be a simple print statement). You then increment n. Finally, you test the value of n; if it is less than 10 you start a new iteration of the loop, otherwise you proceed to the end of the flowchart.
sorry
the following program will display all numbers given in the array in ascending order #include<stdio.h> void main() { int i,h,p; int numbers[10]={5,8,3,2,6,7,9,4,1,10}; for(p=0;p<=8;p=p+1) { for(i=0;i<=8;i=i+1) { if(numbers[i]>numbers[i+1]) { a=numbers[i]; numbers[i]=numbers[i+1]; numbers[i+1]=a; } } } for(i=0;i<=9;i=i+1) { printf("%d ",numbers[i]); } }
Writing a C program that uses dynamic memory allocation to sort names in ascending order is a typical computer science assignment. To write this program, you must be in UNIX.
To write a C++ program to display the student details using class and array of object.
Through a computer program that randomizes numbers.
I know how to do this and you need to know how to do this. Why don't you do your best at writing this program and if it does not work then ask for help. You will not learn anything if I give you the answer.
#include<iostream> int main() { for (int i=0; i<100; ++i) std::cout<<i<<std::endl; }
public class BubbleSortAscendingOrderDemo { public static void main(String a[]) { //Numbers which need to be sorted int numbers[] = {23,5,23,1,7,12,3,34,0}; //Displaying the numbers before sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } System.out.println(); //Sorting in ascending order using bubble sort bubbleSortInAscendingOrder(numbers); //Displaying the numbers after sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } }
iStealer is a program that will steal passwords/serial numbers from your computer.
main (){int i,j,a,n,number[30];printf ("Enter the value of N\n");scanf ("%d", &n);printf ("Enter the numbers \n");for (i=0; i
das
C program for sorting the numbers is very basic, start writing it and if you are having problems, post your program here and a description of the problem and you will be helped. If you are taking a computer course, how do you expect to pass exams if you have plagiarized someone else work for your assignments.