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An array controller is a controller of any array of equivalent hardware components.
int lastLargestIndex(int a[],int n) //a=array, n= number of elements in array { int max=a[0],maxp=0; //max=largest no., maxp= position of largest no. for(int i=0;i<n;i++) if(a[i]>=max) { max=a[i]; maxp=i; } return maxp; }
the length of the array
// largest = largest of a, b, c public class largest { public static void main(String args[]) { int a,b,c,largest; a=0; b=0; c=0; a=Integer.parseInt(args[0]); b=Integer.parseInt(args[1]); c=Integer.parseInt(args[2]); largest=a>b?(a>c?a:c):(b>c?b:c); System.out.println("The largest no. of "+a+","+b+"and"+c+"is"+largest); } }
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An array controller is a controller of any array of equivalent hardware components.
Method 1: Sort the array in descending order, compare 1st and 2nd if not same , return 2nd if same return -1 Method 2: Find the largest number in the array, initialize another array with dimension 1 less than of original. Copy the array elements from the original array minus the largest element. not select largest from the second array and compare with the previous one if not same return the second largest if same return -1
There is no such condition. The algorithm to locate the second largest number in an array of numbers is: Sort the array in descending order. Remove the duplicate values from the array. If there are two or more elements remaining, return the second number. If there is less than two elements remaining, return the NaN value (not a number).
The processor makes no difference in C programming -- the compiler will generate the appropriate instructions for you. To find the largest number in a sequence of numbers, store the numbers in an array. Then invoke the following function, passing the array and its length: unsigned largest (double* num_array, unsigned size) { if (!num_array !size) return size; unsigned max = 0; unsigned index; for (index=1; index<size; ++index) if (num_array[index]>num_array[max]) max = index; return max; } The return value holds the index of the largest value in the array.
knowledge
var largest : integer largest = array[0] for n : integer in array if n > largest largest = n endif endfor return largest
int lastLargestIndex(int a[],int n) //a=array, n= number of elements in array { int max=a[0],maxp=0; //max=largest no., maxp= position of largest no. for(int i=0;i<n;i++) if(a[i]>=max) { max=a[i]; maxp=i; } return maxp; }
A square array is an array in which the number of rows is the same as the number of columns.
#include<stdio.h> #include<conio.h> main() { int a[100]; int n,largest,index,position; printf("enter the number of elements in the array"); scanf("%d",&n); printf("enter %d elements",n); for(index=0;index<n;index++) scanf("%d",&a[index]); largest=a[0]; position=0; for(index=1;index<n;index++) if(a[index]>largest) { largest=a[index]; position=index; } printf("largest element in the array is %d\n",largest); printf("largets element's position in the array is %d\n",position+1); getch(); }
the length of the array
// largest = largest of a, b, c public class largest { public static void main(String args[]) { int a,b,c,largest; a=0; b=0; c=0; a=Integer.parseInt(args[0]); b=Integer.parseInt(args[1]); c=Integer.parseInt(args[2]); largest=a>b?(a>c?a:c):(b>c?b:c); System.out.println("The largest no. of "+a+","+b+"and"+c+"is"+largest); } }
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