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Why memory capacity of 8085 mp is 64 KB?
The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.
Why 4 bit address bus is grounded?
The data bus in the 8086 is 16 bits in size, while the address bus is 20 (16bits would only address 64KB of memory, an extra 4 bits allows to address the total of 1MB, this is done trough segmentation of the memory). To form a multiplexed of data bus and address bus, four bits of 8086 address bus are grounded.
How do you address 1GB memory with 8085 or 8086?
You cannot address 1GB memory with the 8085 or the 8086/8088 without some kind of external demultiplexor that is software controlled. The address bus on the 8085 is 16 bits, giving addressibility of 64KB; while the address bus on the 8086/8088 is 20 bits, giving addressibility of 1MB. To address 1GB, you need a 30 bit address bus.
Which processor had a 32-bit internal bus and a 16-bit external bus?
Which processor has a 32-bit Data Bus and a 24-bit Address Bus?
Size of 8086 address bus?
The 8086/8088 has an internal 20-bit address bus and 16-bit data bus. Externally, the address bus is 20-bits, and the data bus is 16-bits for the 8086 and 8-bits for the 8088.The data bus in the 8086 is 16 bits in size, while the address bus is 20.
Why 8086 requires address bus of 20 bits while using 16 bit address for segement register?
This is due to the fact that 16bits would only address 64KB of memory, which even then was very little. The answer for this was to come up with an extra 4 bits to address the total 1MB, this is done trough segmentation of the memory. Google it.
What is the size of the data bus and the L1 cache on a Core 2 Duo CPU?
64 bit data bus and two L1 (64KB) caches; one L1 cache for each core (cpu)
What is the size of the data bus and l1 cache on a core 2 duo CPU?
64 bit data bus and two L1 (64KB) caches; one L1 cache for each core (cpu)
How multiplixed data and address bus of 8086 can be de-multiplixed?
The 8086 has a 20 bit address bus and a 16 bit data bus. The low order 16 bits of the address bus share the same 16 pins as the data bus. The low order 16 bits of the address are emitted in the first clock cycle of a memory access cycle. External logic is expected to latch that address. Then the bus becomes a data bus. The high order 4 bits of the address bus are handled separately.The determination of operand size (8 bit vs 16 bit) is made by BHE and A0. If BHE is high, it is a 16 bit operand at an even address. If BHE is low and A0 is low, it is an 8 bit operand at an even address. If BHE is low and A0 is high, it is an 8 bit operand at an odd address.
How many Terabytes of memory would a 40 bit address bus be able to address if the system word length was 8bits 16bits 32bits?
1TB is 240 bytes. It follows that a 40 bit address bus can address 1TB. Since 1TB is 1TB regardless of the system's word size, a 40 bit address bus can address 1TB on a computer with an 8 bit, a 16 bit, a 32 bit, or any other word size.
Why you Use Memory Segmentation In 8086 Microprocessor?
The 8086/8088 is a 16 bit processor running on a 16 bit (8086) or 8 bit (8088) bus with a 20 bit address bus. In order to obtain the extra 4 bits of addressibility, Intel designed segment registers that are effectively multiplied by four and then added to the 16 bit offset address generated by the instruction. This yields 64K segments of 64KB each, although they overlap each other at a distance of 16 bytes.
How many address bits does 8085 have?
The 8085 has a 16 bit address bus.
