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How does changing the concentration of a solution affect the kf?
Wiki User
∙ 9y ago
Increasing the concentration of a solute the freezing point depression is increased.
Wiki User
∙ 9y ago
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What concentration of aqueous NaOH solution freezes at -3.2ºC The freezing point of pure water is 0.0ºC and Kf of pure water is -1.86ºC m?
-10.6c
How many moles of KF are contained in 347 g of water in a 0.175m KF solution?
This value is 0,06 moles.
How many moles of KF are contained in 347 g of water in a 0.175 m KF solution?
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
What concentration of aqueous NaOH solution freezes at -32 degrees Celsius the freezing point of pure water is 00 degrees and kf of pure water is -186 degrees Celsius over m?
0.86 m
What is happening with kf?
Kf stands for the freezing point constant of the solvent.
What is the molarity of KF solution containing 116 g of KF in 1.00 L?
The molarity of KF solution containing 116 g of KF in 1.00 L is 2.00 moles.
What is the molarity of a kf(aq) solution containing 116grams of kf in 1.00 liter solution?
4
What concentration of aqueous NaOH solution freezes at -3.2C The freezing point of pure water is 0.0C and Kf of pure water is 1.86Cm?
0.86m
What concentration of aqueous NaOH solution freezes at -3.2ºC The freezing point of pure water is 0.0ºC and Kf of pure water is -1.86ºCm?
0.86 m
What concentration of aqueous NaOH solution freezes at -3.2ºC The freezing point of pure water is 0.0ºC and Kf of pure water is -1.86ºC m?
-10.6c
What concentration of aqueous CaCl2 solution freezes at -10.2ºC The freezing point of pure water is 0.0ºC and Kf of pure water is -1.86ºC m?
0.86 m
How many moles of KF are contained in 347 g of water in a 0.175m KF solution?
This value is 0,06 moles.
How many moles of KF are contained in 347 g of water in a 0.175 m KF solution?
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
What is the vant Hoff factor of MgSO4 for Ki solution at a freezing-point depression of a 0.100 m MgSO4 in 0.225 Celsius?
dt = kf(im) 0.225 = kf(2(0.100m) 0.225 = kf(0.2) 0.225/0.2 = [kf(0.2)]/0.2 1.125 = kf
What concentration of aqueous CaCl2 solution freezes at -10.2ºC. The freezing point of pure water is 0.0ºC and Kf of pure water is -1.86ºCm?
1.83m No srsly, it is. CaCl2 dissociates to form three ions.
What concentration of aqueous NaOH solution freezes at -32 degrees Celsius the freezing point of pure water is 00 degrees and kf of pure water is -186 degrees Celsius over m?
0.86 m
What substance would you add to KF in order to form a buffer solution?
HF
