pH is -log[H(subscript 3)O+]
pOH is the [OH-]
pOH = 14 - pH apex
pH and pOH have an inverse relationship that can be expresses as pH + pOH = 14.
This can be arranged algebraically to pH = 14 - pOH
or to pOH = 14 - pH .
It measures using concentration of OH. it goes opposite of pH on the 0 to 14 scale meaning 14 pOH is a strong acid. 0 pOH is strong base.
pH + pOH =14
The pOH is 6,4.
It will have a pOH of 12. Because pH+pOH=14
pH + pOH =14
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
1.8
pOH is the negative log of the OH- concentration. It is also related to pH by pH + pOH = 14.
pH plus pOH equals 14.
The pH and pOH are related to each other through the equation: pH + pOH = 14 If the pH of a solution is 3, we can find the pOH by rearranging the above equation: pOH = 14 - pH = 14 - 3 = 11 Therefore, the pOH of the solution is 11.