We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
The pH of a solution can be calculated using the formula pH = 14 - pOH. Given that the pOH is 3.31, we can subtract this value from 14 to find the pH. In this case, the pH of the solution would be approximately 10.69.
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.
The pH is 11.
To find the pH of a 0.6 M NaOH solution, first, note that NaOH is a strong base that dissociates completely in water. The concentration of hydroxide ions (OH⁻) will also be 0.6 M. The pOH can be calculated as -log(0.6), which is approximately 0.22. Since pH + pOH = 14, the pH of the solution is about 13.78.
A pOH of 7.0 indicates a neutral solution, not a basic solution. In a basic solution, the pOH would be less than 7.0.
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.
The pOH of a solution can be calculated using the formula pOH = 14 - pH. Therefore, if the pH of a solution is 12.2, the pOH would be 14 - 12.2 = 1.8.
The pOH of a solution can be calculated using the formula: pOH = 14 - pH. For a solution with a pH of 6.2, the pOH would be 14 - 6.2 = 7.8.
10.7(pH) - 14 = 3.3 (pOH)
The pOH can be calculated by subtracting the pH from 14. In this case, since the pH is 10.7, the pOH would be 3.3.
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
pH + pOH = 145.3 + pOH = 14pOH = 14 - 5.3pOH = 8.7
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4
The pH of a solution can be calculated using the formula pH = 14 - pOH. Given that the pOH is 3.31, we can subtract this value from 14 to find the pH. In this case, the pH of the solution would be approximately 10.69.
The pOH is 6,4.
1.8
The pOH of the solution would be 6. If you subtract the pOH from 14 (pH + pOH = 14), you would find that the pH of the solution is 8.