You get an Anti Markovnikov addition to an alkane. The bromide ends up on the less substituted carbon in this instance. Br is the only halogen that is effected by H202. If you were to add HCL and H202 to an alkane, the Cl would attatch to the most heavily substituted carbon (follows Markovnikov).
No it does not affect seed growth!!!!!
HBr
HBr has a dipole
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
No. HBr is a strong acid.
No it does not affect seed growth!!!!!
HBr
You can prepare 13-dibromopropane in the laboratory from lower alkanes or alkyl halides using HBr in the presence of peroxide.
HBr has a dipole
yes HBr is an electrolyte
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
No. HBr is a strong acid.
C18H25NO•HBr
HBr has an ionic bond.
3.21 moles HBr (6.022 X 10^23/1mole HBr) = 1.93 X 10^24 molecules of HBr
HBr is inorganic as it does not contain carbon.
HBr can refer to hydrogen bromide, the covalent molecule and hydrobromic acid which is HBr dissolved i water.