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How does the intensity of a sound wave affect the distance the wave can travel?
Wiki User
∙ 13y ago
the stronger the wave the farther it goes this is because the stronger the wave, the more obstacles it can surpass such as a tree its like a shockwave of an explosion
Wiki User
∙ 13y ago
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How is the intensity of a sound related to the distance between the source and the receiver?
The intensity of a sound will decrease according to an inverse square law.
Does sound Intensity decrease linearly with distance?
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
What is the relation between amplitude and loudness?
Sound is a mechanical wave. This means it needs a material medium to travel through. The loudness ie the intensity of sound is directly proportional to the square of the amplitude. As the sound wave passes through, due to elasticity of the medium the energy will be lost and so the amplitude gets decreased. So at far distance the sound intensity will be very feeble.
By what factor will the sound of a source change the intensity of the waves if the distance is tripled from the sound source?
For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.
By how many times must the distance from a point source be increased to reduce the sound intensity by half?
Increase the distance by 70.7% . To 1.707 times the original distance.
Why does moving away from a radio affect the loudness you hear?
because sound waves spread out, intensity decreases with distance from the source.
What distance is the sound intensity level 25dB?
That depends on the sound intesity level at the point of origen. Sound fall of with the square of the distance but the original intensity must be known.
Can sound travel through oxygen?
Sound can travel through fire as it does not directly affect sound. Sound travels in waves which can pass through solid objects but this limits the distance they can go.
The intensity of a sound describes?
Its loudness at a particular distance
How is the intensity of a sound related to the distance between the source and the receiver?
The intensity of a sound will decrease according to an inverse square law.
How does amplitude affect sound?
Amplitude decides the intensity (loudness) of the sound. Intensity is directly proportional to the square of the amplitude of vibration.
How does the intensity of a sound wave change if the distance from the source is reduced by a factor of 4?
- 6 dB is incorrect. It will decrease by 12 dB.
Does sound Intensity decrease linearly with distance?
No, it follows the inverse square law. That is, the intensity is inversely proportional to the square of the distance. I2/I1 = (r1/r2)². Intensity decreases with 1/r² from increased distance, while the sound pressure decreases only with 1/r from increased distance.
What property of a wave is affected by the amount of energy transported?
Intensity of sound is affected. Intensity is the amount of sound energy passing in unit time. Higher intensity sounds can travel longer distances.
How does the intensity of a sound wave change if the distance from the source increases by a factor of 2?
The intensity increases by a factor of 4-APEX
What is the relation between amplitude and loudness?
Sound is a mechanical wave. This means it needs a material medium to travel through. The loudness ie the intensity of sound is directly proportional to the square of the amplitude. As the sound wave passes through, due to elasticity of the medium the energy will be lost and so the amplitude gets decreased. So at far distance the sound intensity will be very feeble.
By what factor will the sound of a source change the intensity of the waves if the distance is tripled from the sound source?
For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.
