Maximum number of possible electrons in each shell:
K - 2
L - 8
M - 8
N - 18
Maximum number of electrons = 2n2, where n is the number of shell (n = 1 for K, 2 for L, 3 for M, and so on) K shell has 2 electrons maximum L shell has 8 electrons maximum M shell has 18 electrons maximum N shell has 32 electrons maximum O shell has 50 electrons maximum P shell has 72 electrons maximum
there is only one electron in the outermost shell of Na.
Characterise the following 'row': 2, 8, 18, 32, 50, 72, 98 K shell has 2 L shell has 8 M shell has 18 N shell has 32 electrons
The electronic configuration of elements is determined by the energy shells k, l , m, n and so on. K is the first shell L is the second shell and so on. A shell can accommodate 2(n*n) no. of electrons where n is the no. of the shell so the first shell K can accommodate 2(1*1) electrons that is 2 electrons. The atomic no. that is the no. of protons in an atom of the element needs to be known first then as we know that protons are equal in no. to the electrons we will put 2 in K shell 8 in L shell 8 in M shell 2 in N shell then again come back to M shell and fill it to its capacity that is 2(3*3)=18 . By this way you may be able to find the configuration of the first 30 elements easily which will cover up most of the common elements found in chemical reactions.
There are 7 different letters, each to represent each shell. They are: 1. K 2. L 3. M 4. N 5. O 6. P 7. Q
Maximum number of electrons = 2n2, where n is the number of shell (n = 1 for K, 2 for L, 3 for M, and so on) K shell has 2 electrons maximum L shell has 8 electrons maximum M shell has 18 electrons maximum N shell has 32 electrons maximum O shell has 50 electrons maximum P shell has 72 electrons maximum
rubidium
Ammonia is a molecule (NH3) and not an atom.
Phosphorous has 2 elements in K-shell, 8 in L-shell and 5 in M-shell.
there is only one electron in the outermost shell of Na.
Characterise the following 'row': 2, 8, 18, 32, 50, 72, 98 K shell has 2 L shell has 8 M shell has 18 N shell has 32 electrons
They are named as K , L , M , N ... . Where in K is the first shell , L is the second shell , M is the third shell , N is the fourth shell and so on.
the formula for finding out the maximum number of electrons is dependent upon (2n2). n represents the shell, K,L,M,N,O, etc. So if the K shell is the question K is the innermost shell and is represented as 1, so 1 squared is 1, times 2 equals 2! And L is the second shell in the orbit, so 2 squared is 4, times 2 equals 8! M is the third, so 3 squared is 9 times 2 is 18! etc....
The electronic configuration of elements is determined by the energy shells k, l , m, n and so on. K is the first shell L is the second shell and so on. A shell can accommodate 2(n*n) no. of electrons where n is the no. of the shell so the first shell K can accommodate 2(1*1) electrons that is 2 electrons. The atomic no. that is the no. of protons in an atom of the element needs to be known first then as we know that protons are equal in no. to the electrons we will put 2 in K shell 8 in L shell 8 in M shell 2 in N shell then again come back to M shell and fill it to its capacity that is 2(3*3)=18 . By this way you may be able to find the configuration of the first 30 elements easily which will cover up most of the common elements found in chemical reactions.
K,L,M,NN is the fourth shell. It can hold a maximum of 32 electrons.2n2 is the maximum electrons for the energy level (n).
It starts with the following: K shell - 2 electrons L shell - 8 electrons M shell - 18 electrons N shell - 32 electrons it works out from there K being the first etc.
It is because all elements in Period 3 have:2 in K- and 8 in L-shell, both completely filled up,and only 2 (out of max. 8) in the M-shell (being the outer-shell of the 3rd period for group 2).So the electron configuration should be written as:Mg(K,L,M,) = 2, 8, 2,