for example:
long int interrupted [10];
Yes, passing an array name to a pointer assigns the first memory location of the array to the pointer variable. An array name is the same as a pointer to the first location of the array, with the exception that an array name is a r-value, while a pointer is an l-value.
An array element has the same type as the array name.
Yes. The array name is a reference to the array, so you can use sizeof (name) / sizeof (name[0]) to determine the number of elements. Note that sizeof (name) alone gives the length of the array in bytes.
Its type, name and number of elements. char example[12]; // a char array, named 'example' with 12 elements. The name is also a reference to the array itself, referring to the first element in the array (e.g., example == &example[0]).
Array is a class name, hence ought to be a value type.
try this: <function-name> ( <array-name> )
Online I looked up how Susanna Kaysen got the name Girl, Interrupted from, and this is what I got. Girl, Interrupted was the name of a painting which is from Vermeer. The name isnt exactly Girl, Interrupted it is A Girl Interrupted By Her Music. If you are wondering who Vermeer is he was a famous Artist, he was born in October 31, 1632 and he passed away in Decemer 15, 1675. His name is actually Johan Vermeer.
Yes, passing an array name to a pointer assigns the first memory location of the array to the pointer variable. An array name is the same as a pointer to the first location of the array, with the exception that an array name is a r-value, while a pointer is an l-value.
An array element has the same type as the array name.
Yes. The array name is a reference to the array, so you can use sizeof (name) / sizeof (name[0]) to determine the number of elements. Note that sizeof (name) alone gives the length of the array in bytes.
You would insert this command right after your array values have been specified.document.write(name of array[Number on array this item is, starts at 0])
Its type, name and number of elements. char example[12]; // a char array, named 'example' with 12 elements. The name is also a reference to the array itself, referring to the first element in the array (e.g., example == &example[0]).
Will not be interrupted is correct
You have array of type int with a name myArray, and you do not know size of the array.
Array is a class name, hence ought to be a value type.
The array name is a reference to the start address of the array, so simply take its address. int a[10]; int* p1 = &a; If the array is allocated on the heap, then there is no name (all allocations on the heap are anonymous). However, you don't need a name since you already know the address: int* p2 = malloc (10 * sizeof (int));
Cindy Loo Who!