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Power-factor improvement capacitors are connected in parallel with the load, and are rated in reactive volt amperes. If their reactive volt amperes are identical with the reactive volt amperes of the reactive component of the load, then they act to cancel each other, and bring the phase angle to zero (i.e. the load current becomes in phase with the supply voltage). This reduces the value of the load current without affecting the operation of the load, and allows cables and switchgear with lower current ratings to be used than would otherwise be necessary.
The load is the product of the load current and the secondary voltage. So, in this example, the load is 8 x 2000 = 16 000 volt amperes, or 16 kVA. This must not exceed the transformer's rated kVA.
It's impossible to tell unless you know the supply voltage.
304 Amperes
If the voltage is 500 volts, and the power is 200 kilo-watts, then the current is 400 amperes. (Watts equals Volts time Amperes)The resistance of the conductor has nothing to do with this calculation, but that fact that the conductors are 0.1 ohms means that the voltage drop across each conductor is 40 volts. (Volts equals Amperes times Ohms) Since there are two conductors, the total voltage drop is 80 volts, and the voltage available to the load will be 420 volts.
This is an answer that must be determined from the course material. There are several ways to do this.
LxW of building x 3 volt amps per sq. foot
LxW of building x 3 volt amps per sq. foot
LxW of building x 3 volt amps per sq. foot
6 amperes
1 amp, 5 amp depends on the load
The correct expression is 'kilovolt amperes' (kV.A), and it is a multiple the unit of measurement ('volt ampere') for the apparent power of a load in an a.c. circuit -i.e. the product of supply voltage and load current.
12 Amperes is.
Volt Amps conversion
It depends on the voltage and whether it is a single- or three-phase load.
Power-factor improvement capacitors are connected in parallel with the load, and are rated in reactive volt amperes. If their reactive volt amperes are identical with the reactive volt amperes of the reactive component of the load, then they act to cancel each other, and bring the phase angle to zero (i.e. the load current becomes in phase with the supply voltage). This reduces the value of the load current without affecting the operation of the load, and allows cables and switchgear with lower current ratings to be used than would otherwise be necessary.
The load is the product of the load current and the secondary voltage. So, in this example, the load is 8 x 2000 = 16 000 volt amperes, or 16 kVA. This must not exceed the transformer's rated kVA.