I don't think your question is worded exactly right.
It sounds like you are saying Airplane A departs at a speed of 500 m/hr.
An hour later, Airplane B departs at a speed of 600 m/hr.
When will Airplane B catch up to Airplane A.
The question for this is D = R * T
D- distance travelled
R- rate or speed
T- Time
To solve this problem, you have to realize that when Airplane B reaches Airplane A, both aircraft will have traveled the same Distance D.
Now let T be the Time for Airplane A to travel that unknown D.
So first Equation: Airplane A : D = 500*T
For Airplane B, it will have to travel Distance D in that 1 hour less than it took Airplane A to travel it.
Airplane B: D = 600*(T-1)
D is the same in both so the equation becomes
500*T = 600*(T-1)
500*T = 600*T -600
0 = 100 *T - 600
600 = 100*T
T = 6 Hours.
Airplane A travels distance D = 500 * T or 500 *(6) = 3,000 miles in 6 hours.
Airplane B travels the same distance in 5 hours ---so it catches up to it.
So even if this is not your problem, it should demonstrate how to form the problem into 2 Equations and eliminate some of the unknowns which allow you to solve it.
~Custermen~
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