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I don't think your question is worded exactly right.

It sounds like you are saying Airplane A departs at a speed of 500 m/hr.

An hour later, Airplane B departs at a speed of 600 m/hr.

When will Airplane B catch up to Airplane A.

The question for this is D = R * T

D- distance travelled

R- rate or speed

T- Time

To solve this problem, you have to realize that when Airplane B reaches Airplane A, both aircraft will have traveled the same Distance D.

Now let T be the Time for Airplane A to travel that unknown D.

So first Equation: Airplane A : D = 500*T

For Airplane B, it will have to travel Distance D in that 1 hour less than it took Airplane A to travel it.

Airplane B: D = 600*(T-1)

D is the same in both so the equation becomes

500*T = 600*(T-1)

500*T = 600*T -600

0 = 100 *T - 600

600 = 100*T

T = 6 Hours.

Airplane A travels distance D = 500 * T or 500 *(6) = 3,000 miles in 6 hours.

Airplane B travels the same distance in 5 hours ---so it catches up to it.

So even if this is not your problem, it should demonstrate how to form the problem into 2 Equations and eliminate some of the unknowns which allow you to solve it.

~Custermen~

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Q: How long will it take for an airplane that leaves one half hourlater than an airplane flying at rate of five hundred miles per hour when the first airplane flying six hundred miles per hour?
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