Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.
2.30 x 6.023 x 1023 = 13.85 x 1023
You think probable to dinitrogen pentoxide - N2O5.
The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?
10.25L
3,42 moles of phosphorus trichloride have 469,6686 g.
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
The formula shows that 2 aluminum atoms are present in each formula unit, which is, for ionically bonded compound, the alternative to "molecule" for a covalently bonded compound. The formula unit for aluminum itself is generally considered to consist of single atom. Therefore, 0.5 mole of the compound will contain 1.00 moles of aluminum.
The chemical name dinitrogen tetrafluoride establishes that each molecule contains exactly 2 nitrogen atoms. A mole always contains Avogadro's Number of molecules. Therefore, the required answer is 4.19 X 2 X Avogadro's Number, or 5.05 X 1024 atoms, to the justified number of significant digits.
4 g of Helium = 1 mole.So, 56 g of helium = 14 moles
Approx 3.29 moles.
5 moles