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The formula shows that 2 aluminum atoms are present in each formula unit, which is, for ionically bonded compound, the alternative to "molecule" for a covalently bonded compound. The formula unit for aluminum itself is generally considered to consist of single atom. Therefore, 0.5 mole of the compound will contain 1.00 moles of aluminum.

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What is the name of the compound with the formula al2so43?

The compound with the formula Al2(SO4)3 is called aluminum sulfate. It is composed of two aluminum ions (Al3+) and three sulfate ions (SO4 2-).


How many moles of sulfate ions are there in a 0.20 Liter solution of 0.030 molar aluminum sulfide and oxygen?

To find the moles of sulfate ions in the solution, you first need to determine the moles of aluminum sulfide present. Since you are not provided with the amount of aluminum sulfide, you cannot calculate the moles of sulfate ions. Additionally, oxygen is not relevant to determining the moles of sulfate ions.


How many moles of chloride ions are in 0.2520g of aluminum chloride?

To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.


How many chloride ions are there in 3 mol of aluminum chloride?

Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.


How many moles of Aluminum Sulfate are present when 0.12 moles of each compound is dissolved in water?

Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*

Related Questions

How many fluoride ions are in 1.46 moles of aluminum fluoride?

There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.


What is the name of the compound with the formula al2so43?

The compound with the formula Al2(SO4)3 is called aluminum sulfate. It is composed of two aluminum ions (Al3+) and three sulfate ions (SO4 2-).


How many moles of sulfate ions are there in a 0.20 Liter solution of 0.030 molar aluminum sulfide and oxygen?

To find the moles of sulfate ions in the solution, you first need to determine the moles of aluminum sulfide present. Since you are not provided with the amount of aluminum sulfide, you cannot calculate the moles of sulfate ions. Additionally, oxygen is not relevant to determining the moles of sulfate ions.


How many moles of O2- ions are in 0.65 moles of aluminum oxide?

The formula for aluminum oxide is Al2O3, which means that, if aluminum oxide is ionically bonded, every formula mass of aluminum oxide contains three O-2 ions. In this instance, 0.65 formula masses of aluminum oxide would contain 3 X 0.65 or 1.95 moles of O2-. If aluminum oxide were covalently bonded, it would not contain any O-2 ions.


How many moles of chloride ions are in 0.2520g of aluminum chloride?

To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.


How do you calculate moles of ions in 0.200 moles aluminum perchlorate.?

0,6 moles of (ClO4)3- and 0,2 mol Al


How many moles of aluminum ions are in 45.0 g of aluminum oxide?

Steps to take: Write the chemical formula : Al2O3 Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide. Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2. Then you have calculated the number of Ions.


How many moles of sulfate ions (SO42) are present in 1.7 moles of Al2(SO4)3?

There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.


How many chloride ions are there in 3 mol of aluminum chloride?

Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.


What is the ratio of aluminum ions to sulfur ions in the formula Al2S3?

The ratio of aluminum ions to sulfur ions in the formula Al2S3 is 2:3. This means that for every 2 aluminum ions, there are 3 sulfur ions present in the compound.


How many ions are in 1.33 moles of PO4-3?

The number of moles is 8,00944733981.10e23.


How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?

5,7 moles (SO4)3-.