The formula shows that 2 aluminum atoms are present in each formula unit, which is, for ionically bonded compound, the alternative to "molecule" for a covalently bonded compound. The formula unit for aluminum itself is generally considered to consist of single atom. Therefore, 0.5 mole of the compound will contain 1.00 moles of aluminum.
The compound with the formula Al2(SO4)3 is called aluminum sulfate. It is composed of two aluminum ions (Al3+) and three sulfate ions (SO4 2-).
To find the moles of sulfate ions in the solution, you first need to determine the moles of aluminum sulfide present. Since you are not provided with the amount of aluminum sulfide, you cannot calculate the moles of sulfate ions. Additionally, oxygen is not relevant to determining the moles of sulfate ions.
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
The compound with the formula Al2(SO4)3 is called aluminum sulfate. It is composed of two aluminum ions (Al3+) and three sulfate ions (SO4 2-).
To find the moles of sulfate ions in the solution, you first need to determine the moles of aluminum sulfide present. Since you are not provided with the amount of aluminum sulfide, you cannot calculate the moles of sulfate ions. Additionally, oxygen is not relevant to determining the moles of sulfate ions.
The formula for aluminum oxide is Al2O3, which means that, if aluminum oxide is ionically bonded, every formula mass of aluminum oxide contains three O-2 ions. In this instance, 0.65 formula masses of aluminum oxide would contain 3 X 0.65 or 1.95 moles of O2-. If aluminum oxide were covalently bonded, it would not contain any O-2 ions.
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
0,6 moles of (ClO4)3- and 0,2 mol Al
Steps to take: Write the chemical formula : Al2O3 Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide. Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2. Then you have calculated the number of Ions.
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
Aluminum chloride contains 3 chlorine atoms per molecular unit. Therefore, in 3 moles there are 3 times Avogadro's number of chloride ions = 1.807 X 1024.
The ratio of aluminum ions to sulfur ions in the formula Al2S3 is 2:3. This means that for every 2 aluminum ions, there are 3 sulfur ions present in the compound.
The number of moles is 8,00944733981.10e23.
5,7 moles (SO4)3-.