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Q: How many Moles is 573.28 of Ag Cl?
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How many moles is in 0.0688 Ag Cl


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How many moles is 573.28 g of AgCl?

Remember the equation moles = mass(g) / Mr Mr is the relative molecular mass. Refer to the Periodic Table 1 x Ag = 1 x 107.87 1 x Cl = 1 x 35.5 107.87 + 35.5 = 143.37 (Mr of AgCl) Substituting moles(AgCl) = 573.28 / 143.37 = 3.9986... ~ 4 moles (AgCl)