0,5 moles Cl-
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
For this problem you need the atomic masses of the elements to find the molecular mass (added atomic masses). Then take the atomic mass of Cl and divide it by the molecular mass (multiplied by 100) to get a percent. This will be the percent of Cl in all compounds of HCl. Then you can use this percent and apply it to the 2 moles.H- 1.00Cl- 35.5HCl- 36.535.5 / 36.5 × 100 = 97.3% Cl in HClSo we know that in 2 moles of HCl, 97.3% of it is Cl.97.3% of 2.00 moles HCl = 1.95 moles of Cl in 2 moles HClNow we have to find out how many atoms this is (convert moles to atoms). Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023.1.95 moles Cl × 6.02 × 1023 = 1.17 × 1024atoms of Cl in 2 moles of HCl
This depends on the concentration of sodium chloride in water.
Ionic bond since you are bonding a non-metal with a metal.
How many moles is in 0.0688 Ag Cl
0,5 moles Cl-
Ag +1, Cl -7
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
+1 for Ag, -1 for Cl
slightly
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
Bromide: Ag+ + Br- = AgBr which is a cream precipitate Chloride: Ag+ + Cl- = Ag Cl which is a white precipitate Iodide: Ag+ + I- = AgI which is a yellow precipitate
+1 for Ag -1 for Cl
slightly
Remember the equation moles = mass(g) / Mr Mr is the relative molecular mass. Refer to the Periodic Table 1 x Ag = 1 x 107.87 1 x Cl = 1 x 35.5 107.87 + 35.5 = 143.37 (Mr of AgCl) Substituting moles(AgCl) = 573.28 / 143.37 = 3.9986... ~ 4 moles (AgCl)