For this problem you need the atomic masses of the elements to find the molecular mass (added atomic masses). Then take the Atomic Mass of Cl and divide it by the molecular mass (multiplied by 100) to get a percent. This will be the percent of Cl in all compounds of HCl. Then you can use this percent and apply it to the 2 moles.
H- 1.00
Cl- 35.5
HCl- 36.5
35.5 / 36.5 × 100 = 97.3% Cl in HCl
So we know that in 2 moles of HCl, 97.3% of it is Cl.
97.3% of 2.00 moles HCl = 1.95 moles of Cl in 2 moles HCl
Now we have to find out how many atoms this is (convert moles to atoms). Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023.
1.95 moles Cl × 6.02 × 1023 = 1.17 × 1024atoms of Cl in 2 moles of HCl
The number of atoms is 12,044 281 714.10e23 atoms.
3 x 10^-24 molecules
This is just easy. there are 4 atoms.
The number of molecules is 12,044280.10e23.
12.044e+23 moleculs
One mole is 6.02 × 1023 molecules. So 2 molecules out of that 6.02 × 1023 would be 2/(6.02 × 1023) or 3.32 ×10-24 moles.
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
6.022 x 1023 x 2 = 1.2044 x 1024
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
Because it ionizes into Na+ and Cl-, thus ONE mole or molecule of NaCl produces TWO moles or molecules, namely Na and Cl, thus i (the van't Hoff factor) is 2.
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
The number of molecules is 12,044280.10e23.
12.044e+23 moleculs
The chemical equation is N2 + 3H2 -> 2NH3 So reacting 2 moles of N2 will produce 4 moles ammonia.
Two Chloride ions (2Cl-) ions are needed with their -1 charge on each one to cancel out the +2 charge of the single Magnesium ion (Mg2+). So Magnesium Chloride would have the chemical formula: MgCl2
One mole is 6.02 × 1023 molecules. So 2 molecules out of that 6.02 × 1023 would be 2/(6.02 × 1023) or 3.32 ×10-24 moles.
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
MgCl2 is an ionic compound with the Mg2+ cation and the Cl- anion in a 1:2 ratio. In each formula unit of MgCl2 there are two Mg2+ and one Cl- ion. So in 4 moles of MgCl2 there will be 12 moles of ions.
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
2 moles.