12.044e+23 moleculs
One mole is 6.02 × 1023 molecules. So 2 molecules out of that 6.02 × 1023 would be 2/(6.02 × 1023) or 3.32 ×10-24 moles.
3.6 moles hydrogen atoms (1 mole water/2 mole H)(6.022 X 1023/1 mole water molecules) = 1.1 X 1024 molecules of water =======================
The number of molecules is 12,044280.10e23.
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
No, this would make 5 moles. This is because water is H2O. This means that for each oxygen molecule used, there will be 2 hydrogen molecules used. In the given equation Only 5 moles of oxygen could be used to pair with all 10 moles of hydrogen, therefore giving you an excess of 5 oxygen molecules.
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
One mole is 6.02 × 1023 molecules. So 2 molecules out of that 6.02 × 1023 would be 2/(6.02 × 1023) or 3.32 ×10-24 moles.
3.6 moles hydrogen atoms (1 mole water/2 mole H)(6.022 X 1023/1 mole water molecules) = 1.1 X 1024 molecules of water =======================
4 moles of oxygen atoms are present in 4 moles of H2O
The number of molecules is 12,044280.10e23.
The reaction requires 2 moles of hydrogen gas and 1 mole of oxygen gas to produce 2 moles of water.
The chemical equation is N2 + 3H2 -> 2NH3 So reacting 2 moles of N2 will produce 4 moles ammonia.
1 mole of water is 18g. 36g of water is thereforeequivalent to 2 moles. 2 moles of water contains 4 moles of hydrogen and 2 moles of oxygen and so there are6 moles of atoms in 2 moles of water. 6 moles of atoms x (3.6x10^24) = 36.1x10^24 atoms
yes
6 moles COULD be produced
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
2 moles.