The formula unit for this compound has a gram molar mass that is the sum of the gram atomic masses for its two constituent atoms, 22.989 + 35.483 = 58.472. Therefore, 2.1 g constitutes 2.1/58.472 = 0.0359 mole. Multiplying this number of moles by Avogadro's number, which is 6.022 X 1023, gives the number of atoms of sodium, 2.2 X 1022 atoms of sodium.
NA+ and Cl-
A sodium ion. Cation. Na+ A chlorine ion. Anion Cl- Forms NaCl, sodium chloride.
Yes, NaCl is in an ionic bond because there is an attraction between the oppositely charged ions Na+ and Cl-
A NaCl solution is a mixture. It has Na+ ions, Cl- ions and water.
Dissociation of what? Table salt, for example (NaCl) dissociates into Na+ and Cl- ions in water.
2
Na+ + Cl- --> NaCl NaCl = salt.
one
Na+ + Cl- --> NaCl NaCl = salt.
NA+ and Cl-
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================
30 g NaCl = 0.513 mol NaCl So No. of Na+ ions = 3.088 X 1023 So No. of Cl- ions = 3.088 X 1023
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
In each formula unit of NaCl there is one Na+ ion. Therefore, amount of sodium ions = amount of NaCl = 4.25mol
Sodium chloride is dissociated in water:NaCl-------------------------------------Na+ + Cl-
There are two types of elements, sodium (Na) and chlorine (Cl) in NaCl and they exist as ions: Na+ and Cl- ions