The current is half an amp because amps times volts equals watts.
It depends on how many amperes there are. If you have 1 amperes, then you get 260 watts. If you have 260 amperes, then you have 67,600 watts. If you have 0.001 amperes, then you have 0.26 watts. Its just watts = volts times amperes. Of course, the limiting factor is the available power behind the 260 volts, but you did not say anything about that.
Pwer is volts times amperes. 120 volts times 10 amperes = 1.2 KW
Watts = volts x amperes. So if your region uses 110 volts, 20 amperes is equivalent to 2200 watts; if your region uses 220 volts, 20 amperes is equivalent to 4400 watts.
Power (watts) = current (amperes) * voltage (volts) Current (amperes) = voltage (volts)/resistance (ohms) 120 watts = current * 120 volts current = 1 ampere 1 ampere = 120 volts/resistance resistance = 120 ohms
Volts.
Considering an incandescent bulb and using P=VxI P= Power Watts V= Volts I= Current (amperes) I=P/V I=75Watts/120Volts = 0.625 Amperes (A or Amps) Therefore the current through a 75watt bulb that is connected to a 120volt circuit is 0.625 amps.
It depends on how much current it's putting out. An inverter rated at 800 volt-amperes can deliver 220 volts at 3.636 amperes, or it can deliver 110 volts at 3.727 amperes.
It depends on how many amperes there are. If you have 1 amperes, then you get 260 watts. If you have 260 amperes, then you have 67,600 watts. If you have 0.001 amperes, then you have 0.26 watts. Its just watts = volts times amperes. Of course, the limiting factor is the available power behind the 260 volts, but you did not say anything about that.
Kilowatts are never converted to kilovolts. There's no direct relationship between them, without involving other quantities in the circuit. Watts = (volts) times (amperes) Kilowatts = (kilovolts) times (amperes) Kilovolts = kilowatts/amperes
Given R=? I=12 ampere V=120 Volts equation I=V divided R Solution; R=12 ampere 120 Volts answer (10)
Power dissipation in a resistor, or any other type of load, for that matter, is measured in watts and calculated as volts times amperes. It does not matter if the resistor is in a series or a parallel circuit, so long as the volts and amperes in the calculation is for that one resistor. Obviously, volts and amperes is distributed amongst the components of a circuit, and series vs parallel can have a significant affect on that distribution, so you will need to calculate or measure them on a case by case basis.
A voltmeter does not measure current, it measures voltage in units named volts. An ammeter measures current in units named amperes or amps in common shorthand. A voltmeter is connected in parallel to the circuit being measured, whereas an ammeter is connected in series with the circuit being measured.
1.5 volts
36 volts
VAC means volts AC, and is a measure of the voltage in an AC circuit.KVA means kilovolt-amperes, and is a measure of the power in a circuit. For a resistive load, KVA is the same as KW, or kilowatts.The two terms are not related in that you can not compare one to another without also knowing the current flowing in the AC circuit. VAC * IAC = KVA, when all values are in RMS (not peak to neutral or peak to peak quantities).
I = E/R = 120/25 = 4.8 amperes
You can't really convert that. If you multiply volts and amperes, you get watts, a unit of power. Watts is equivalent to joules/second. If you multiply volts x amperes x seconds, you get joules.