You can't really convert that. If you multiply volts and amperes, you get watts, a unit of power. Watts is equivalent to joules/second. If you multiply volts x amperes x seconds, you get joules.
The resistance of a 230v and 10 amp circuit is 23 ohms.
Ohm's law: resistance = voltage / current
The total resistance of the circuit increases. hence the new resistance after adding the resistance will be new resistance = old resistance + added Resistance There is a small mistake in the question. The second word is 'changes' not 'charges'
For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.
The net effective resistance of 5 ohms, 10 ohms, and 20 ohms in series is 35 ohms.The current through the net effective resistance is [ I = E/R ] = 120/35 = 3.429 Amp. (rounded)Note: If you try this at home, be aware that these resistors will dissipatethe 5 ohm . . . 58.8 wattsthe 10 ohm . . . 117.6 wattsthe 20 ohm . . . 235 watts .These are no ordinary resistors, such as hang on the wall in plastic bags at Radio Shack.These would have to be 'power' resistors ... like heating coils in a toaster or hair-dryer.
-- If the 20 ohms and the nother 10 ohms are configured in series, then the totalnet effective resistance is 30 ohms.-- If they are configured in parallel, then the total effective resistance is 62/3 ohms.
No, ammeters have a low internal resistance. This is so that when they are put in series with a circuit, they change the circuit's operating characteristics as little as possible.Contrast this with voltmeters, which do have a high internal resistance, and which are intended to be placed in parallel with the circuit they are measuring.Use the link below to the related question on why ammeters have a low internal resistance and read through that information to see why things are the way they are.
Resistance = (voltage across the circuit) divided by (current through the circuit) =12 / (3 x 10-3) = 4 KΩ
maybe 10 amperes
Assuming DC and resistive loads, resistance equals voltage across the load, divided by the current through it. In this case 120/10 or 12 ohms.
80% of the rated circuit. 10 amp circuit is 8 amps, 20 amp circuit is 16 amps, etc.
No, # 10 wire is only rated at 30 amp maximum.
Resistance is Volts over Current 11 Ohm = 110Volt / 10 Amp
30 amp wired with AWG # 10 wire.
V=IR where V is voltage, I is current and R is resistance. You want to know what the current will be in a series circuit based on the resistance. You need to know the voltage as well as the resistance, gives you the equation as follows I=V/R So if you have 10 volts and a 1 ohm resistor, the current will be 10 amps. If you increase the resistor to 10 ohms, your current will then be 1 amp. In a parallel circuit, the resistance is equal to the sum of the inverse. For example. If I have two resistors of 2 ohms each in parallel, the equation would be 1/2 + 1/2 = 0.5 + 0.5 = 1 In that particular instance, your current would increase.
NO! Using a larger amp fuse defeats the purpose of the fuse to protect the wiring in the circuit. This can cause a fire. Always use the correct amp fuse for that circuit.
NO! Using a larger amp fuse defeats the purpose of the fuse to protect the wiring in the circuit. This can cause a fire. Always use the correct amp fuse for that circuit.
Not a good thing to do! If you are blowing 10 amp fuses, you have a problem with that circuit. Putting a 30 amp fuse in its place can do more damage.
yes bailed 40 round bales with bailer hook up to a 10 amp circuit