Actually, the question itself does not provide enough information as required to provide an answer. To determine wattage, both amperage and voltage must be known, and voltage has not been stated in the question.
Only an educated guess can be given as an answer. Specifically, knowing that "63 amp" is a common rating for a pin & sleeve type IEC 60309 interconnect used outside of North America, a "63 amp" connector is most commonly deployed with single-phase power distribution systems that provide a Phase voltage of 220V, 230V or 240V. Thusly, because amperage multiplied by voltage provides watts, some possible answers are:
13.86kW (63A x 220V)
14.49kW (63A x 230V)
15.12kW (63A x 240V)
If the power system is a three-phase 220/380V, 230/400V or 240/415V type, multiply the kW values above by a factor of "3".
AnswerYour question doesn't actually make any sense, I'm afraid, as you are referring to three entirely different quantities and units of measurement.
As these are all different quantities, you cannot equate one with the other!
the line voltage ,which is necesary to calculate kilowatts, is missing.
Up to sixty three amps.
?
8,33 Amps
A 1-HP motor is reckoned to draw 7 amps at 240 v single-phase. The same power of motor would draw 3.5 amps at 480 v single-phase, but a 480 v supply could most likely be a three-phase suppy, and the current in that case would be reckoned as 2 amps.
180 amps. Assuming the panel will be loaded only 80%.
It means 225 amps on each phase.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
8,33 Amps
24 amps. This could be three 11.54 resistors connected in star, or three 34.6 ohm resistors connected in delta.
50 Amps Single Phase 20 Amps Three Phase
A 1-HP motor is reckoned to draw 7 amps at 240 v single-phase. The same power of motor would draw 3.5 amps at 480 v single-phase, but a 480 v supply could most likely be a three-phase suppy, and the current in that case would be reckoned as 2 amps.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
180 amps. Assuming the panel will be loaded only 80%.
To answer this question the voltage of the heater must be given. I = W/E.
It means 225 amps on each phase.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
read the name plate on the motor
There are actually three pieces to this puzzle - resistance. And you're missing that one.