How many amps in 8 ohm using ohm's law?

Answer 1

You must know the applied voltage to determine the answer. According to Ohm's law:

I = E/R (current equals voltage divided by resistance)

So, if the voltage were, say, 16 volts, then the current through the 8 ohm resistor would be two amps:

2 = 16 / 8

Answer 2

You are trying to compare apples with elephants. Ohms is a measure of resistance and amps measures current.

There are two important formulas when calculating Voltage, Current, Resistance and wattage. Ohm's Law states that Voltage = Current x Resistance; and Watts = Current x Voltage x PF, where PF is the power factor and has a value from zero to 1. For a purely resistive load the PF is 1 so the formula is simplified to Watts = Current x Voltage. PF decreases for loads like motors or lights with ballasts.

Answer 3

Ohms(R) is the amount of resistance of the load in a given circuit, where as, amps(I) is the amount the load uses in current, ie: a 60 watt(P) light bulb uses half an amp at 120 volts(E) AC. Using the 'PIE' method, P / I X E 60 / .5 X 120, if you place = at any of the other signs, the sum will equal the means, now solve for the ohms value using E / I X R, 120 / .5 = 240. This is the simplest form to finding the value of a circuit. So, the answer to the question is, they are two totally independent things that are bound to each other and inversely affect one another, in a circuit. If ohms increases, current decreases when voltage stays the same, as when ohms decreases, current increases with the voltage staying the same.

Answer 4

According to Ohm's law,

I=E/R

meaning current (amps) equals voltage (volts) divided by resistance (ohms).