kVA = 1000va
Therefore 1000/220
Answer 4.54A
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
Different controllers have different outputs depending on how many valves are on each zone. In the device there is a control transformer. Look for the VA output of the transformer's secondary side. Mine states 20 VA at 24 volts. To find the amperage use the following equation. I = W/V. Amps = Watts or VA/Volts. Mine can output 20 divided by 24 = .83 amps. This amperage will be the maximum output in amps that the controller can produce to operate the zone valves. To find the current draw of the primary side of the transformer divide the transformers VA by 120 volts.
20.44 kva
The 220 Volt secondary in a single phase transformer rated 2kVA, should be able to deliver about 2000/220 or 9.1 Amperes, assuming unity power factor.
You have your own answer. It is 1.5 amps.
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
A transformer does not use, it transforms voltage from one value to another. The output amperage is governed by the connected load. If the load wattage is higher than the wattage rating of the transformer then either the primary or secondary fuse will blow or the transformer will burn up if the fusing is of the wrong sizing. The maximum primary amperage can be found by using the following equation, Amps = Watts/Volts, A = W/E = 600/120 = 5 amps. The same equation is used for the calculating the maximum secondary amperage, A = W/E = 600/12 = 50 amps.
2.083 amps
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
You will need a 3:1 ratio transformer. An output current of 20 amps and a secondary voltage of 47 volts, results in a transformer rated at 940 VA.
Take the KVA and divide it by the voltage. 25/.230 = 109 amps. The transformer can put out up to 50% more that its rated for short durations. So you could get around 150 amps out of a 25 Kva tranformer in a worst case situation.
It depends on the rated voltage of its secondary.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
Different controllers have different outputs depending on how many valves are on each zone. In the device there is a control transformer. Look for the VA output of the transformer's secondary side. Mine states 20 VA at 24 volts. To find the amperage use the following equation. I = W/V. Amps = Watts or VA/Volts. Mine can output 20 divided by 24 = .83 amps. This amperage will be the maximum output in amps that the controller can produce to operate the zone valves. To find the current draw of the primary side of the transformer divide the transformers VA by 120 volts.
20.44 kva
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
The primary current of a transformer depends upon the secondary current which, in turn, depends upon the load supplied by the transformer. There is not enough information in the question to determine the rated primary and secondary currents of the transformer.