This information should be taken from the motors name plate. Motor manufactures differ by small amounts even on the same horsepower. The electrical code book for calculation purposes rates a 150 HP, 3 PH, 460V motor at 180 running amps.
The line to neutral voltage on a 480 v system is 277 v and with 25 hp or 25x746 watts per phase the current would ideally be 67 amps. However due allowance must be made for the efficiency of the motor and the power factor, so the current could be 30% more, 90 amps.
150 HP is equivalent to 111.9 kW so allowing for 90% conversion efficiency it would draw 124.3 kW of power. With a power factor of 0.85 the motor would draw 146.3 kVA from the supply.
The motor would need 48.76 kVA from each phase and with a line-to-neutral voltage of 120 v the estimated current would be 406 amps.
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The equation for amperage when horsepower is known is; A = 746 x HP/1.73 x V x pf x eff.
A standard motor's efficiency between 5 to 100 HP is .84 to .91.
A standard motor's power factor between 10 to 100 HP is .86 to .92.
So A = 746 x 150 = 111900/(1.73 x 208 x .91 x .92) = 111900/301 = 372 amps.
180
It depends on the size and type of the motor being started.
The code book states that the motor will draw 1.8 amps. <<>> 1 amp
You asked the wrong question. You need to know how many amps the motor uses. Then you can multiply amps times volts and get watts. Then you can multiply watts by hours and get watt hours. (For house electricity you pay for kilowatt hours.) A kilowatt is 1,000 watts.
A 1-HP motor is reckoned to draw 7 amps at 240 v single-phase. The same power of motor would draw 3.5 amps at 480 v single-phase, but a 480 v supply could most likely be a three-phase suppy, and the current in that case would be reckoned as 2 amps.
A pool pump motor which is drawing half the amps listed on its nameplate can indicate a problem with the windings or a lack of incoming current. Pumps will only draw as many amps as are required to operate under the current load.
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To answer this question the voltage of the motor must be stated.
Depends on how big the motor is. A stronger motor will draw more amps then a weaker or less efficient motor. For example a wiper motor draws far less then a starter motor.
It depends on the size and type of the motor being started.
Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
It depends on the voltage-- I think at 110v it's 4 amps per hp
Depends on the voltage. If you are running off 120 VAC, a 0.5 horsepower motor would draw 3.1 A.
The code book states that the motor will draw 1.8 amps. <<>> 1 amp
read the name plate on the motor
You asked the wrong question. You need to know how many amps the motor uses. Then you can multiply amps times volts and get watts. Then you can multiply watts by hours and get watt hours. (For house electricity you pay for kilowatt hours.) A kilowatt is 1,000 watts.
Then you are trying to get more HP out of the motor that it can supply. Back off on the load that the motor is driving or put a bigger motor onto the load.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%