From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
Balanced equation first. 4P + 5O2 -> 2P2O5 8.00 mole O2 (2 mole P2O5/5 mole O2) = 3.20 moles P2O5 produced
It's 97g/195.1g Pt = .497 .497 x 6.022x10^23= 2.993 mols/atom.
5 kilogram = how many grams 5 kilogram = how many grams 5 kilogram = how many grams
740 grams P2O5 (1 mole P2O5/141.94 grams)(6.022 X 10^23/1 mole P2O5) = 3.14 X 10^24 atoms of P2O5
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
Assuming 0.75 g of P2O5,moles of P2O5 = 0.0053 moles1 molecule of P2O5 has 7 atoms.so reqd. no. is 2.23 X 1022.
The formula P2O5, could itself represent one molecule of diphosphorus pentoxide. Or you could specify any number of moles. One mole of P2O5 would be 6.022 x 1023 molecules of P2O5. Two moles would be 1.204 x 1024 molecules, and so on.
The atom doesn't contain gram which is a unit of mass.
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
1 atom-gram of uranium = 238,02891 grams
1.66 × 10^-24 grams per nucleon. So you need to know what element you are interested in, then look at the atomic mass number to find out how many nucleons (protons + neutrons) are in the atom, and multiply by 1.66 x 10^-24
an atom weighs about 1o trillionths of a trillionth of a trillionth of a gram that is all I know.
There is 25.0 moles Oxygen
Balanced equation first. 4P + 5O2 -> 2P2O5 8.00 mole O2 (2 mole P2O5/5 mole O2) = 3.20 moles P2O5 produced
25x6.022x10^23=1.5x10^25p2o5=7atom7(1.5x10^25)