6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
100 g of anhydrous copper sulfate (CuSO4) contain 39,81 g copper.
63.55g or 63.55 grams
1.20 × 1024 atoms
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
63.54 g/mol
If density of Copper is 8.9 g/cm3, then 534 g, not 530 g, for a 30 cm X 20 cm X .10 cm
The density of copper is 10.0 g/mL. What is the volume in milliliters of a 2184-g ingot of copper?
100 g of anhydrous copper sulfate (CuSO4) contain 39,81 g copper.
One mole of oxigen (O2-the diatomic molecule) is needed for 127,092 g copper to form CuO.
Cd= 24.23718445g
63.55g or 63.55 grams
0.450 Kg
0,688 g calcium is equivalent to 0,017 moles.
if 75grams of oxygen react how many frams of aluminum are required
1.20 × 1024 atoms