Fe1mol Fe =2.27×1024 atoms F
one mole of a compound contain 6.022x1023 particles(molecules) and therefor in two moles of iron there will be 2x6.022x1023 molecules.since atomic state of iron(Fe)is its molecular state,IT WILL CONTAIN 2X6.022X1023 iron atoms...
1 mole is quantify 6.022 x 10^23 atoms or molecules. It just need to multiply 0.652 with 6.022 x 10^23
how many atoms of iron are present in 0.025 molar of iron
1 molar =6.022x1023 atoms
2.1 x (6.02x1023) = 1.26x1024 iron atoms.
tera abbs
10715600000000000000000
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
481,7713432.1023 atoms
10715600000000000000000
Five iron atoms have a mass of 1.3155 x 10-22 grams.
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
5.0x10^25 * (1 mol / 6.022x10^23 atoms) = 83 moles of iron.
Molar mass of iron = 55.845g/mol (atomic weight in grams/mol) 1mol Fe atoms = 6.022 x 1023 atoms Fe 10g Fe x 1mol/55.845g x 6.022 x 1023 atoms/mol = 1.078 x 1023 atoms
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
There are 1.204 x 1023 atoms in .200 mol of Pb.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
1.3 mol
481,7713432.1023 atoms