answersLogoWhite

0

How many atoms in CBr4?

Updated: 8/10/2023
User Avatar

Wiki User

6y ago

Best Answer

It is 1 calcium atom and 2 bromine atoms which totals 3 atoms

User Avatar

Wiki User

11y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

12y ago

There are 3 atoms

This answer is:
User Avatar

User Avatar

Wiki User

6y ago

Carbon tetrabromide has five atoms.

This answer is:
User Avatar

User Avatar

Wiki User

14y ago

3 atoms

This answer is:
User Avatar

User Avatar

Wiki User

13y ago

5

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many atoms in CBr4?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many carbon atoms are in CBr4?

1


How many molecules are in 325g of CBr4?

325 g of CBr4 have 5,9.10e23 molecules.


How many ATOMS of carbon are present in 4.25 moles of carbon tetrabromide?

According to Avagadro's number one mole of any substance is equal to 6.022*10^23 particles. Knowing this you can calculate the number of atoms in 4.25 moles of carbon tetrabromide easily: 4.25(moles of carbon tetrabromide) * 6.022*10^23(atoms) = 2.559*10^24 So 2.559*10^24 atoms are present in 4.25 moles of carbon tetrabromide.


How many electron dose CBr4 have?

152


What is the chemical formula for the compound containing one carbon atom for every four bromine atoms?

CBr4 = carbon tetrabromide


One chemical formula containing one carbon atom for four bromine atoms?

This compound is the carbon tetrabromide - CBr4.


How many covalent bonds are peresent in CBr4?

Four.


Why does the compound ncl5 not exist?

Carbon atoms have 4 valence electrons, so it can form only 4 bonds. CBr5 would require carbon to form 5 bonds. A molecule composed of carbon and bromine atoms would be CBr4, which is carbon tetrabromide.


What is the symbol for CBr4?

CBr4 , this is the correct formula for carbon-tetra-bromide


Is CBr4 metal or non-metal?

Yes


How many molecules are in 393g of CBr4?

The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23


Will CBr4 and H2O form homogeneous solutions when combined?

No. CBr4 is nonpolar and H2O is polar. Both do not mix.