341 grams scandium (1 mole Sc/44.96 grams)(6.022 X 1023/1 mole Sc)
= 4.57 X 1024 atoms of scandium
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To find the number of atoms in a sample of scandium, you need to first calculate the number of moles using the molar mass of scandium (44.96 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. 341g of scandium is approximately 7.58 moles, which corresponds to 4.57 x 10^24 atoms.
The chemical formula for scandium sulfide is Sc2S3. Therefore, in one molecule of scandium sulfide, there are 2 scandium atoms and 3 sulfur atoms, totaling 5 atoms.
Scandium hydroxide has one scandium atom (Sc), three oxygen atoms (O) and three hydrogen atoms (H) per formula unit. Therefore, there are a total of seven atoms in one molecule of scandium hydroxide.
There are approximately 6 x 10^22 atoms in a 12.0 gram sample of sodium.
Scandium has 1 electron in its d subshell.
The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / moleTo convert moles to atoms:atoms Sc = 0.638 mol Sc6.02 x 1023 atoms Sc = 3.84E+23 atoms Sc1 mol ScMultiply by atoms per mole. Moles cancel out.
The chemical formula for scandium sulfide is Sc2S3. Therefore, in one molecule of scandium sulfide, there are 2 scandium atoms and 3 sulfur atoms, totaling 5 atoms.
The gram atomic mass of scandium is 44.9559. From the definition of Avogadro's Number, one gram atomic mass of any element contains 6.022 X 1023 atoms of the element. 341/44.9559 constitutes about 7.585 gram atomic masses and therefore contains (7.585)(6.022 X 1023) or 4.57 X 1024 atoms of scandium, to the justified number of significant digits.
Scandium hydroxide has one scandium atom (Sc), three oxygen atoms (O) and three hydrogen atoms (H) per formula unit. Therefore, there are a total of seven atoms in one molecule of scandium hydroxide.
341g = 12.03oz
In scandium, the number of electrons in each energy level can be calculated using the formula 2n^2, where n is the principal quantum number representing the energy level. Scandium has 21 electrons, so it would have 2 electrons in the first energy level (n=1), 8 electrons in the second energy level (n=2), and 11 electrons in the third energy level (n=3).
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The number of atoms is 1,50553521.10e23.
Approx. 9.1024 atoms.
1,600
There are approximately 1.04 x 10^25 carbon atoms in a 12.5 kg sample of carbon. This can be calculated using Avogadro's number and the molar mass of carbon.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
To determine the number of half-lives that have elapsed, we first find the total number of atoms in the sample, which is 500 (125 + 375). The starting atom would have been from 250 atoms of C-14. To find the number of half-lives elapsed, we divide the total number of atoms by the starting amount (500/250). This gives us 2 half-lives that have elapsed.