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41,1 g of sodium sulfate (Na2SO4, anhydrous) contain 10,455.10e23 atoms.

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Q: How many atoms are there in 41.1 g of sodium sulfate (Na2SO4)?
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How many atoms are represented in one unit of sodium sulfate?

The formula for sodium sulfate is Na2SO4. Therefore, there are 2 sodium atoms, one sulfur atom, and 4 oxygen atoms, for a total of 7.


How many types of atoms are present in Na2SO4?

Na2SO4Three different types of atoms.2 atoms of sodium.1 atom of sulfur.4 atoms of oxygen.This compound is called,sodium sulfate.


How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?

How many grams of Na+ are contained in 25 g of sodium sulfate (Na2SO4)?


How many grams of sodium are there in 10 g of sodium sulfate Na2SO4?

3.23


How many atoms each element are in 2Na2SO4?

You probable think to sodium sulfate, Na2SO4. Na2SO4 has: 7 atoms total - 2 sodium, 1 sulfur and 4 oxygen. 2Na2SO4 (two molecules) have 14 atoms.


How many atoms does sodium sulfide have?

Sodium Sulfate is Na2SO4 and so there are 7 atoms in the molecule.


How many moles of atoms are contained in 2.88g na2 so4?

Full formal set up. 2.88 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(6.022 X 1023/1 mole Na2SO4)(1 mole Na2SO4 atoms/6.022 X 1023) = 0.020 moles of sodium sulfate atoms ------------------------------------------------------( you can see the last two steps are superfluous )


How many grams of sodium are there in 10.0 grams of sodium sulfate?

Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------


How many grams of HCl are needed to make 21.5 grams of Na2SO4?

Sodium sulfate is not prepared from hydrogen chloride.


How many Na2SO4 molecules are present in 1.125 moles?

1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.


How many grams are in 3.6 moles of sodium sulfate?

3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )


How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?

Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================