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6.747 moles of lead (6.022 X 10^23/1 mole Pb)
= 4.063 X 10^24 atoms of lead
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∙ 13y ago
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How many atoms are there in 80 grams of lead?
Pb has a MW of 207.2 g/mol. Thus, 80g of Pb is 80/207.2 = 0.39 mol of lead. Using Avogadro's number: (6.0221415 * 1023 atoms/mol)(0.39 mol) = 2.349 * 1023 atoms.
How many mol of potassium are represented by 7.85e23 potassium atoms?
1.3 mol
How many atoms are present in 8.00 mol atoms?
48,177 134 32.1023 atoms
How many hydrogen atoms are in 0.63 mol of (NH4)2SO4?
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
How many atoms are in 0.188 mol Na?
1.13x10^23
How many atoms are there in 80 grams of lead?
Pb has a MW of 207.2 g/mol. Thus, 80g of Pb is 80/207.2 = 0.39 mol of lead. Using Avogadro's number: (6.0221415 * 1023 atoms/mol)(0.39 mol) = 2.349 * 1023 atoms.
How many atoms of sodium na are in 7 mol of sodium answer in units of atoms?
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
How many atoms are present in 1.5 mol of sulfuric acid?
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
How many atoms are in 0.200 mol of pb?
There are 1.204 x 1023 atoms in .200 mol of Pb.
How many atoms are there in 6.755 mol Pb?
6.755 moles lead (6.022 X 1023/1 mole Pb) =6.755 x 6.022 X 1023 =4.068 X 1024 atoms of lead =====================
How many atoms of sodium are in 2.35 mol of NaCl?
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
How many sulfur atoms are in 0.45 mol BaSO4?
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
How many mol of potassium are represented by 7.85e23 potassium atoms?
1.3 mol
How many atoms fit across the period at the end of this sentence?
Assuming you are talking about a period made by carbon atoms (Pencil lead is almost pure carbon) and that period has a mass of 0.0001g Then the answer is 5x1018 atoms.There are 12.011g of carbon per mol, there are 6.022x1023 atoms per mol.1mol | 6.022x1023 atoms | 0.001 g |-----------|--------------------------|-------------| = 5x1018 atoms/period12.011g | 1 mol | period |
How many atoms of oxygen are in 0.50 mol of CaNO32?
The answer is 18,061.1023 atoms.
How many atoms are present in 80.0 mol of zirconium?
481,7713432.1023 atoms
How many atoms are present in 8.00 mol atoms?
48,177 134 32.1023 atoms
