There are 3 atoms in each molecule of Potassium Hydroxide.The molecular formula is KOH. Hence, there is one atom of Potassium, one of Oxygen and one of Hydrogen.
The answer is 12,831 g KOH.
35.28 (g) / 56.1056 (g/mol) = 0.6288 mol KOH
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
4.44 g KOH x 1 mole KOH/56 g = 0.0793 moles KOH(x L)(0.142 mole/L) = 0.0793 molesx = 0.558 L = 558 mls neededHCl + KOH ==> KCl + H2O
1 fomula unit of KOH has 3 atoms: 1 potassium (K), 1 oxygen (O), and 1 hydrogen (H).
There are 3 atoms in each molecule of Potassium Hydroxide.The molecular formula is KOH. Hence, there is one atom of Potassium, one of Oxygen and one of Hydrogen.
The answer is 12,831 g KOH.
Molar mass of KOH = 39.1+16.0+1.0 = 56.1Amount of KOH = mass of sample / molar mass = 32/56.1 = 0.570mol
The answer is10,436 g.
1 mole of KOH is 56.1074 grams1.350 g/56.1074 g =0.02406 (2.406 x 10^-2) moles of KOH
Atoms: 1 of potassium, 1 of manganese and 4 of oxygen.Total atoms: 6
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
K+ and OH- is KOH -----------
35.28 (g) / 56.1056 (g/mol) = 0.6288 mol KOH
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