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35.28 (g) / 56.1056 (g/mol) = 0.6288 mol KOH
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How many milliliters of 0.142 M HCl would be required to titrate 4.44 g KOH?
4.44 g KOH x 1 mole KOH/56 g = 0.0793 moles KOH(x L)(0.142 mole/L) = 0.0793 molesx = 0.558 L = 558 mls neededHCl + KOH ==> KCl + H2O
How do you make 0.1m KOH?
An 11 M KOH solution indicates there are 11 moles of KOH per liter of water. 1 mole of KOH has a volume of 27.4 mL, so to account for the added volume it is necessary to add 15.75 moles of KOH per liter of water, or 884 grams per liter.
How many grams of KOH are present in 31.5 mL of a 7.26M KOH solution?
The answer is 12,831 g KOH.
How many moles are in 23.34 g of NaCl?
The answer is 0,4 moles.
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles of KOH are represented by 1.350g of KOH?
1 mole of KOH is 56.1074 grams1.350 g/56.1074 g =0.02406 (2.406 x 10^-2) moles of KOH
In the reaction MgCl2 plus 2KOH---Mg(OH)2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
How many moles of KOH are contained in 750. mL of 5.00 M KOH solution?
Molarity = moles of solute/volume of solution 0.500 M KOH = moles KOH/125 ml 62.5 millimoles, or to answer the question precisely, 0.0625 moles KOH
In the reaction MgCl2 plus 2KOH to MgOH2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
Which equation shows how to calculate how many grams (g) of KCl would be produced from 4 mol KOH?
4 mol KOH/1 x 2 mol KCI/2 mol KOH x 74.55 g KCI/1 mol KCI Apex.
How many milliliters of 0.142 M HCl would be required to titrate 4.44 g KOH?
4.44 g KOH x 1 mole KOH/56 g = 0.0793 moles KOH(x L)(0.142 mole/L) = 0.0793 molesx = 0.558 L = 558 mls neededHCl + KOH ==> KCl + H2O
Which equation shows how to calculate how many grams(g) of Mg(OH)2 would be produced from 4 mol KOH. The balanced reaction is mgcl2 plus 2koh mg(oh)2 plus 2kcl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Which equation shows how to calculate how many grams (g) of Mg(OH)2 would be produced from 4 mol of KOH The balanced reaction is MGCl2 plus 2KOH Mg(OH)2 plus 2KCl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
How do you prepare 0.002N methanolic KOH?
Molar mass KOH = 56g/mol and 0.002 N KOH = 0.002 moles/L0.002 moles/L x 56 g/mole = 0.112 g/LDissolve 0.113 grams KOH in 1 liter or methanol, or any fraction/multiple thereof. For example, dissolve 0.0113 g KOH in 100 mls or dissolve 0.226 g in 2 liters of methanol.
How do you make 0.1m KOH?
An 11 M KOH solution indicates there are 11 moles of KOH per liter of water. 1 mole of KOH has a volume of 27.4 mL, so to account for the added volume it is necessary to add 15.75 moles of KOH per liter of water, or 884 grams per liter.
How many grams of KOH are present in 31.5 mL of a 7.26M KOH solution?
The answer is 12,831 g KOH.
How many grams of KOH are in 37.5 mL of 4.96M KOH solution?
The answer is10,436 g.
