0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
Sulfur comes in many different forms. Commonly it comes in a ring of 8 atoms (S8). In a mole of S8 molecules there would be 4.82x1024 atoms of sulfur.
One mole of particles = 6.02x1023 particles
Each molecule of S8 has 8 sulfur atoms.
6.02x1023 x 8 = 4.82x1024.
1 mole of anything contains 6.02 x 1023 atoms. 4.5 moles contain 4.5 x 6.02 x 1023 atoms = 2.709 x 1024 atoms
1.8066x1024
One mole (mol) of anything is 6.022x1023 items, usually molecules, but also atoms.
4.3 moles of sulfur (6.022 X 10^23/1 mole S)
= 2.6 X 10^24 atoms of sulfur
Any mole of an element has 6,022 140 857.10e23 atoms.
4.00 g S x 1 mol/32.07g x 6.02x10^23 atoms/mole = 7.51x10^22 atoms
7.51 x 1023 atoms of sulfur
The number of atoms is 12,044.10e23.
The number of atoms in 0.40 mole of ANY element or compound is: 0.40 mol x 6.022x1023 atoms/mol = 2.4x1023 atoms.
3.6 mol Sulphur (S8) molecules = 3.6 X 8 X 6.023 X 1023 atoms of Sulphur i.e 1.7346 X 1025 atoms
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
1 mol Sulfur is 32 g Sulfur So 2.5 mol Sulfur is 80 g Sulfur
Assuming you are talking about pure sulfer. Atomic weight of Sulfer is : 32.07g/mol 100g / 32.07 g/mol = 3.06 mol (rounded to nearest 2 decimal place) 1 mol = 6.022 141 79 × 1023 atoms. 3.06 X 6.022 141 79 × 1023 = 1.82 X 10^24 atoms
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
1.51 x 1023
The number of atoms in 0.40 mole of ANY element or compound is: 0.40 mol x 6.022x1023 atoms/mol = 2.4x1023 atoms.
To find the number of sulfur atoms in a given mass of sulfur, you can use the following steps: Determine the number of moles of sulfur using the formula: moles = mass molar mass moles= molar mass mass โ Given that the molar mass of sulfur ( S S) is 32.06 g/mol and the mass ( m m) is 1.56 g: moles = 1.56 โ g 32.06 โ g/mol moles= 32.06g/mol 1.56g โ Once you have the moles of sulfur, you can use Avogadro's number (6.022 x 1 0 23 10 23 mol โ 1 โ1 ) to find the number of atoms: number of atoms = moles ร Avogadroโs number number of atoms=molesรAvogadroโs number Let's calculate it: moles = 1.56 โ g 32.06 โ g/mol โ 0.0488 โ mol moles= 32.06g/mol 1.56g โ โ0.0488mol number of atoms = 0.0488 โ mol ร ( 6.022 ร 1 0 23 โ mol โ 1 ) number of atoms=0.0488molร(6.022ร10 23 mol โ1 ) number of atoms โ 0.0488 ร 6.022 ร 1 0 23 number of atomsโ0.0488ร6.022ร10 23 number of atoms โ 3.0 ร 1 0 22 number of atomsโ3.0ร10 22 Therefore, there are approximately 3.0 ร 1 0 22 3.0ร10 22 sulfur atoms in 1.56 g of sulfur.
Aluminum sulfide is Al2S3, which has 3 sulfur atoms per formula unit. 1.10mol means 1.10(6.02x1023), which is 6.62x1023 formula units. Multiple that by 3 to get your sulfur atoms: 6.62x1023(3) = 1.99x1024 sulfur atoms.
2.408 x 10^24 atoms.
3.6 mol Sulphur (S8) molecules = 3.6 X 8 X 6.023 X 1023 atoms of Sulphur i.e 1.7346 X 1025 atoms
Note that one mole equals 6.022x10^23 of anything in converting. In this case, 1 mole=6.022x10^23 atoms. So we take 0.40 mol of S and convert to calculate how many atoms there are. 0.40 mol S x 6.022x10^23 atoms S/mol S = 2.41x10^23 atoms S
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
1 mol Sulfur is 32 g Sulfur So 2.5 mol Sulfur is 80 g Sulfur
Assuming you are talking about pure sulfer. Atomic weight of Sulfer is : 32.07g/mol 100g / 32.07 g/mol = 3.06 mol (rounded to nearest 2 decimal place) 1 mol = 6.022 141 79 × 1023 atoms. 3.06 X 6.022 141 79 × 1023 = 1.82 X 10^24 atoms
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol