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NaHCO3 has how many atoms?
6 atams
How many atoms of oxygen are in two molecules of NaHCO3?
NaHCO3 has 3 atoms (the subscript number of O) in 1 molecule, so .... in two molecules ....., you see
How many atoms make up the compound NaHCO3?
Na 1 H 1 C 1 O 3 6
How many grams are in 1 mol nahco3?
1 mole of NaHCO3 Na = 1 * 22.99 g = 22.99 g H = 1 * 1.01 g = 1.01 g C = 1 * 12.01 g = 12.01 g O = 3 * 16.00 g = 48.00 g Total = 84.01 g There are 84.01 grams in one mole of NaHCO3.
What mass of C6H8O7 is needed to consume 0.42g of NaHCO3?
0.567 moles NaHCO3 (3mol O/1mol NaHCO3)(6.022 X 10^23/1mol O) = 1.02 X 10^24 atoms of oxygen.
NaHCO3 has how many atoms?
6 atams
How many atoms of oxygen are in two molecules of NaHCO3?
NaHCO3 has 3 atoms (the subscript number of O) in 1 molecule, so .... in two molecules ....., you see
What atoms make up baking powder and what is it's chemical formula and atomic formula?
NaHCO3 NaHCO3
How many atoms make up baking soda?
Baking soda is an ionic compound so it wont be a molecule. The formula is NaHCO3. It has 2 names: sodium bicarbonate or sodium hydrogen carbonate. It has 6 atoms in total. 1 sodium/Na, 1 hydrogen/H, 1 carbon/C, and 3 oxygen/O.
How many atoms α̲̅re in a baking soda formula?
baking soda is NaHCO3 and has 6 atoms totally Na - 1 H - 1 C - 1 O - 3
How many atoms make up the compound NaHCO3?
Na 1 H 1 C 1 O 3 6
What atoms are in baking soda?
The chemical formula of baking soda is NaHCO3. The molecule contain atoms of sodium, hydrogen, oxygen and carbon.
How many items does 2 NaHCO3 have?
Which items are you asking about? This a chemical compound and it has 2 sodium, 2 hydrogen, 2 carbon, and 6 oxygen atoms.
How many atoms of hydrogen are in a baking soda molecule?
Technically none, since the hydrogen present is in the form of H+, as part of the ionic compound NaHCO3.
How many moles of NaHCO3 are present in a 6.10 g sample?
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
How many grams are in 1 mol nahco3?
1 mole of NaHCO3 Na = 1 * 22.99 g = 22.99 g H = 1 * 1.01 g = 1.01 g C = 1 * 12.01 g = 12.01 g O = 3 * 16.00 g = 48.00 g Total = 84.01 g There are 84.01 grams in one mole of NaHCO3.
What mass of C6H8O7 is needed to consume 0.42g of NaHCO3?
0.567 moles NaHCO3 (3mol O/1mol NaHCO3)(6.022 X 10^23/1mol O) = 1.02 X 10^24 atoms of oxygen.
