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Suppose:
- formula of 'hair' is (averaged by) C10H18O5N2S and so this is with 36 atoms in one 'molecule'
- Its formula mass is (averaged by) [10*12.0+18*1.0+5*16.0+2*14.0+1*32.0] = 260 g/mol
- and the mass of one hair is (averaged by) 1.0 mg
The answer can now be calculated, (controlled by 'unit analysis')
[1.0*10-3(g) / 260(g/mol)] * 6.022*10+23(molecules/mol) * 36 (atom/molecule) =
8*10+19 atoms (+/- 10%) per hair of 1 mg.
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∙ 13y ago
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