First you have to find out the number of moles of Nickel in 0.63g. Do this by dividing 0.63 by the molecular weight of Nickel; 58.69g. 0.63/58.69= 0.01 mol (2 d.p.) In one mole there are 6.02x1023 atoms. Therefore in 0.01 moles of Nickel there will be: 0.01 x 6.02x1023 = 9.15x1015 atoms.
1.3 mol
48,177 134 32.1023 atoms
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
1 mole of nickel is 58.69 grams. 176.1 g Ni * (1 mol Ni/58.69 g Ni) = 3.0005 mol Ni Therefore, 176.1 grams of nickel is equal to 3 moles of nickel.
Nickel is 58.7g/mol, so 26.4/58.7=0.45mol, and that times 6.02x1023 (Avogadro's number) gives you 2.71x1023 atoms of nickel.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
9.3*10^15 atoms nickel = ? grams take the number of atoms, divide by one mole and then times by the molar mass of nickel 9.3*10^15atoms /6.02*10^23 atom/mol * 58.69 g/mol =9.1*10^-7 grams
There are 1.204 x 1023 atoms in .200 mol of Pb.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
It depends on how many grams you have. Are you asking for nickel acetate's atomic mass?
First you have to find out the number of moles of Nickel in 0.63g. Do this by dividing 0.63 by the molecular weight of Nickel; 58.69g. 0.63/58.69= 0.01 mol (2 d.p.) In one mole there are 6.02x1023 atoms. Therefore in 0.01 moles of Nickel there will be: 0.01 x 6.02x1023 = 9.15x1015 atoms.
1.3 mol
481,7713432.1023 atoms
The answer is 18,061.1023 atoms.