Nickel is 58.7g/mol, so 26.4/58.7=0.45mol, and that times 6.02x1023 (Avogadro's number) gives you 2.71x1023 atoms of nickel.
To find the mass of 5.97 x 10^27 nitrogen atoms, calculate the molar mass of nitrogen (14.01 g/mol) and then multiply by the number of atoms. Using Avogadro's number (6.022 x 10^23 atoms/mol), you would find that the mass of 5.97 x 10^27 nitrogen atoms is approximately 1.68 grams.
There are approximately 163,163 atoms of carbon in 0.020 g of carbon.
How many lithium atoms are in 10.56 g of lithium
2.32
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To find the number of moles of nickel atoms in 125 g of nickel, divide the given mass by the molar mass of nickel. The molar mass of nickel is approximately 58.69 g/mol. Therefore, 125 g Ni / 58.69 g/mol = ~2.13 moles of Ni atoms.
125 g nickel is equivalent to 2,13 moles.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
6,687.1023 chlorine atoms
The number of atoms of lead is 6,68.10e23.
5 g of sulfur contain 0,94.10e23 atoms.
To find the mass of 5.97 x 10^27 nitrogen atoms, calculate the molar mass of nitrogen (14.01 g/mol) and then multiply by the number of atoms. Using Avogadro's number (6.022 x 10^23 atoms/mol), you would find that the mass of 5.97 x 10^27 nitrogen atoms is approximately 1.68 grams.
The answer is 3.32*10^23 atoms
There are approximately 163,163 atoms of carbon in 0.020 g of carbon.
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
For plutonium 239: ca. 74,68.1023 atoms
The number of atoms is 28,099.10e23.