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What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
What mass of hydrogen contains the same number of atoms as 7.00g of nitrogen?
Let's see. 7.00 grams nitrogen (1 mole N/14.01 grams)(6.022 X 10^23/1 mole N) = 3.01 X 10^23 atoms of nitrogen 3.01 X 10^23 ( 1mole H/6.022 X 10^23)(1.008 grams/1 mole H) = 0.504 grams of hydrogen
What mass of nitrogen is needed to make 34 grams of ammonia?
To find the mass of nitrogen needed to make ammonia, first determine the molar mass of ammonia (NH3) which is 17 g/mol. Since there is one nitrogen atom in ammonia, the nitrogen mass is 14 g/mol. To make 34 grams of ammonia, you would need 14 grams of nitrogen.
Calculate mass of 3.011 x 10 23 no of nitrogen atoms?
To calculate the mass of 3.011 x 10^23 nitrogen atoms, first find the molar mass of nitrogen which is 14.01 g/mol. Then, divide the number of atoms by Avogadro's number (6.022 x 10^23) to get the number of moles. Finally, multiply the number of moles by the molar mass to find the mass of the atoms. The calculation would be 3.011 x 10^23 / 6.022 x 10^23 = 0.5 moles, then 0.5 moles x 14.01 g/mol = 7.005 grams.
The formula for nitrogen dioxide is NO2 What is the molar mass of nitrogen dioxide to the nearest gram?
The molar mass of nitrogen (N) is approximately 14 grams/mole, and the molar mass of oxygen (O) is approximately 16 grams/mole. Therefore, the molar mass of nitrogen dioxide (NO2) is 14 + (2*16) = 46 grams/mole to the nearest gram.
What is the mass of nitrogen in grams?
One mole of atoms of an element is equal to the atomic mass of that element expressed in grams. Nitrogen-14 so one mole of nitrogen weighs 14 g
What is the mass of 3.01.1021 atoms of nitrogen?
To find the mass of 3.01 x 10^21 atoms of nitrogen, you would first calculate the molar mass of nitrogen (14.01 g/mol). Then, convert the number of atoms to moles by dividing by Avogadro's number (6.022 x 10^23), and multiply by the molar mass to get the mass. The mass of 3.01 x 10^21 atoms of nitrogen would be approximately 63.5 grams.
How do you calculate the number of atoms in 6980 of nitrogen?
To calculate the number of atoms in 6980 grams of nitrogen, you would first convert the mass of nitrogen to moles using the molar mass of nitrogen (~14 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Overall, the calculation would be 6980 grams of nitrogen * (1 mol / 14 grams) * (6.022 x 10^23 atoms / 1 mol).
How do you convert 2.2 grams in to atoms in nitrogen?
To convert grams to atoms, you need to first convert grams of nitrogen to moles using its molar mass (14.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, for 2.2 grams of nitrogen: Convert grams to moles: 2.2 g / 14.01 g/mol = 0.157 moles. Convert moles to atoms: 0.157 moles x 6.022 x 10^23 atoms/mol = 9.46 x 10^22 atoms of nitrogen.
What is the mass in grams of 6.022 x 1023 N atoms of mass 14.01 amu?
The molar mass of any element is its atomic weight (amu) in grams, and 1 mol of any element is 6.022 x 1023 atoms. Therefore, the mass in grams of 6.022 x 1023 atoms of N = 14.01g N.
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
What mass of hydrogen contains the same number of atoms as 7.00g of nitrogen?
Let's see. 7.00 grams nitrogen (1 mole N/14.01 grams)(6.022 X 10^23/1 mole N) = 3.01 X 10^23 atoms of nitrogen 3.01 X 10^23 ( 1mole H/6.022 X 10^23)(1.008 grams/1 mole H) = 0.504 grams of hydrogen
How much nitrogen is in 7.5 grams of ammonia?
First you need to find the atomic masses of each element involved in the compound NH3, and add them up to find the total molecular mass of ammonia.Nitrogen = 14.0 gramsHydrogen = 1.01 × 3 atoms = 3.03 grams----------------------------------------------------Ammonia = 17.03 gramsThen you take the mass of nitrogen in one molecule and divide it by the total mass to find the percent composition.14.0 grams Nitrogen ÷ 17.03 grams Ammonia = .822 = 82.2% nitrogen in ammoniaThen you simply need to take 82.2% of 7.5 grams to find how much nitrogen is in that particular amount.82.2% × 7.50 = 6.17 grams of nitrogen in 7.50 grams of ammonia
What mass of nitrogen is needed to make 34 grams of ammonia?
To find the mass of nitrogen needed to make ammonia, first determine the molar mass of ammonia (NH3) which is 17 g/mol. Since there is one nitrogen atom in ammonia, the nitrogen mass is 14 g/mol. To make 34 grams of ammonia, you would need 14 grams of nitrogen.
How many grams of N combine with 7.05x1022 O atoms in N2O5?
The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.
How many moles of nitrogen in 42 grams of nitrogen?
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
Calculate mass of 3.011 x 10 23 no of nitrogen atoms?
To calculate the mass of 3.011 x 10^23 nitrogen atoms, first find the molar mass of nitrogen which is 14.01 g/mol. Then, divide the number of atoms by Avogadro's number (6.022 x 10^23) to get the number of moles. Finally, multiply the number of moles by the molar mass to find the mass of the atoms. The calculation would be 3.011 x 10^23 / 6.022 x 10^23 = 0.5 moles, then 0.5 moles x 14.01 g/mol = 7.005 grams.
