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7.00 grams nitrogen (1 mole N/14.01 grams)(6.022 X 10^23/1 mole N)

= 3.01 X 10^23 atoms of nitrogen

3.01 X 10^23 ( 1mole H/6.022 X 10^23)(1.008 grams/1 mole H)

= 0.504 grams of hydrogen

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Q: What mass of hydrogen contains the same number of atoms as 7.00g of nitrogen?
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