To find the mass of 2 grams of nitrogen (N) atoms, we first recognize that the Atomic Mass of nitrogen is approximately 14 grams per mole. Therefore, 2 grams of nitrogen corresponds to about ( \frac{2 , \text{g}}{14 , \text{g/mol}} \approx 0.143 , \text{moles} ) of nitrogen atoms. This means we have approximately ( 0.143 \times 6.022 \times 10^{23} \approx 8.6 \times 10^{22} ) nitrogen atoms in 2 grams.
To find the number of argon atoms in 1.5x10^2g of argon, we first need to determine the molar mass of argon. The molar mass of argon is approximately 39.95 g/mol. Next, we convert the given mass to moles by dividing by the molar mass. Finally, we use Avogadro's number (6.022x10^23) to convert moles to atoms. The number of argon atoms in 1.5x10^2g of argon would be approximately (1.5x10^2g / 39.95g/mol) x 6.022x10^23 atoms.
The molar mass of any element is its atomic weight (amu) in grams, and 1 mol of any element is 6.022 x 1023 atoms. Therefore, the mass in grams of 6.022 x 1023 atoms of N = 14.01g N.
The water is 38g and the salt 2g, so long as there is nothing else in the water
1.19x10^21 atoms of Na
To calculate the grams of zinc containing 6x10^23 atoms, we need to determine the molar mass of zinc, which is approximately 65.38 g/mol. Then, we can use Avogadro's number to find the number of moles (n) of zinc atoms: n = (6x10^23 atoms) / (6.022x10^23 atoms/mol). Finally, we can calculate the mass of zinc: mass = n x molar mass.
To find the mass of 8.2 x 10²² atoms of N₂I₆, first determine the number of molecules, which is equal to the number of atoms divided by the number of atoms in one molecule of N₂I₆ (which contains 8 atoms). This gives approximately 1.025 x 10²² molecules. The molar mass of N₂I₆ is about 360.8 g/mol. Therefore, the mass in grams can be calculated by multiplying the number of molecules by the molar mass and dividing by Avogadro's number (6.022 x 10²³), resulting in approximately 57.4 grams.
To find the mass of 3.01 x 10^21 atoms of nitrogen, you would first calculate the molar mass of nitrogen (14.01 g/mol). Then, convert the number of atoms to moles by dividing by Avogadro's number (6.022 x 10^23), and multiply by the molar mass to get the mass. The mass of 3.01 x 10^21 atoms of nitrogen would be approximately 63.5 grams.
The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.
moles to atoms you multiply the number of moles by avogadros number ex: 1.32 mol x (6.022 x 10^23 atoms)/mol mass to atoms you multiply the mass (in grams) times the molar mass of the element or compound (ex: N 14.01 mols/gram) then times avogadros number once you have the moles. ex: 45.6 g N x (14.01 mol/gram) x (6.022 x 10 ^23 atoms/mol) if it's a compound instead of an element, find the molar mass of the compound (the molar masses of all the elements in it added up) and multiply by it. ------------------------- Actually you are wrong, from mass to atoms you need to take the initial mass divide by the gram of the element that you are doing and multiply by the Avogadros number
2g is about the mass of a small paper clip.
Yes, gas has mass. The mass of a gas is determined by the number of gas particles present and the type of gas molecules. The mass of gas can be measured using a balance or by determining the mass of the container before and after the gas is added.
To find the proportion of N in Ca3N2, we calculate the total atomic mass of N in the compound which is 2 * 14 = 28 (since there are 2 nitrogen atoms in Ca3N2). The total atomic mass of Ca3N2 is 3 * 40 + 2 * 14 = 136. Therefore, the proportion of N in Ca3N2 by mass is 28/136 = 0.206 (or 20.6%).