CH4 has a molecular weight of 16, which makes the math easy.
Each mole of carbon has a weight of 12. Each carbon binds with 2 oxygen to make CO2. The oxygen weighs 16. CO2 weighs 12+2*16=44 grams.
Each mole of hydrogen weighs 1 g. 2 Hydrogens bind with 1 oxygen to make H2O, which has a weight of 18g. There are 4 hydrogen atoms available so we make 2 water molecules with a total weight of 36g.
The total mass of products of combustion for 16 g of methane is about 80 g.
Divide the mass by molecular mass.trhen multiply by 6.02 × 10 23
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
You have to divide 10 by molecular mass.Then get the answer.So the answer is 0.625
Methane is an elementary organic compound having the molecular formula of CH4. Methane is composed of carbon (C) and hydrogen (H) atoms. The molecular weight of CH4 is 16. 01 grams per mole.
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
First divide 88.9 by 16.Then multiply it by 6.022x10^23.Then mutiply answer by five
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
You have to divide 10 by molecular mass.Then get the answer.So the answer is 0.625
Methane is an elementary organic compound having the molecular formula of CH4. Methane is composed of carbon (C) and hydrogen (H) atoms. The molecular weight of CH4 is 16. 01 grams per mole.
Percentage of hydrogen in methane is 25%. Percentage of hydrogen = mass of hydrogen/mass of methane x 100 mass of hydrogen = 1 x 4= 4 and mass of carbon = 12. Since methane has 4 hydrogen atoms and one carbon atom therefore mass of methane = 16 Percentage of hydrogen = 4/16 x 100 =25
16
16oz = 453.6g
2 LiH2PO4 contain 16 atoms.