Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
To find the number of molecules in 1.0g of CH4, you need to first calculate the number of moles of CH4 using its molar mass (16g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, in 1.0g of CH4, there are approximately 3.01 x 10^22 molecules.
The formula for methane is CH4, showing that each molecule contains exactly 5 atoms. Therefore, the number of atoms in 0.650 ml is 5 X 0.650 X Avogadro's Number, or about 1.96 X 1024 atoms, to the justified number of significant digits.
To calculate the number of molecules in 21.6 grams of CH4, you need to first determine the molar mass of CH4 (methane). The molar mass of CH4 is approximately 16 g/mol. Next, divide the given mass (21.6 g) by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
Divide 96 by molecular mass.So the answer is 6mol
The balanced equation for the reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. 1 mole of CH4 produces 1 mole of CCl4. Calculate moles of CH4: 5.14 g / 16.04 g/mol = 0.32 mol. 0.32 mol of CH4 will produce 0.32 mol of CCl4, which is 0.32 * 153.82 g/mol = 49.18 g of CCl4.
To find the number of molecules in 1.0g of CH4, you need to first calculate the number of moles of CH4 using its molar mass (16g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, in 1.0g of CH4, there are approximately 3.01 x 10^22 molecules.
The formula for methane is CH4, showing that each molecule contains exactly 5 atoms. Therefore, the number of atoms in 0.650 ml is 5 X 0.650 X Avogadro's Number, or about 1.96 X 1024 atoms, to the justified number of significant digits.
One mole is equal to 6.022 x 1023 of anything. In this case, we are looking for molecules. So 1 mole=6.022 x 1023 molecules. We have 2.3 moles, so we want to know how many molecules are there. 2.3 mol CH4 x 6.022x1023 molecules CH4 / mol CH4 = 1.38x1024 molecules of CH4
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
To calculate the number of molecules in 21.6 grams of CH4, you need to first determine the molar mass of CH4 (methane). The molar mass of CH4 is approximately 16 g/mol. Next, divide the given mass (21.6 g) by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
There are (5.41 \times 10^{23}) molecules of (O_2) in 0.900 moles.
Divide 96 by molecular mass.So the answer is 6mol
1 mole is 6.022*10^23 "things," so 1 mole of CH4 (methane) contains (1.00 mol) * (6.022*10^23 molecules/mole) = 6.022*10^23 molecules However, each atom of methane includes four atoms of hydrogen, so the number of H atoms is: (6.022*10^23 molecules) * (4 H atoms/molecule) = 24.088*10^23 atoms
The answer is 12,046.1023 molecules.
The balanced equation for the reaction is: CH4 + 4Cl2 -> CCl4 + 4HCl. 1 mole of CH4 produces 1 mole of CCl4. Calculate moles of CH4: 5.14 g / 16.04 g/mol = 0.32 mol. 0.32 mol of CH4 will produce 0.32 mol of CCl4, which is 0.32 * 153.82 g/mol = 49.18 g of CCl4.
There are 0.75 moles in it.You have to devide 12 by molecular mass
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.