1 mole is 6.022*10^23 "things," so 1 mole of CH4 (methane) contains
(1.00 mol) * (6.022*10^23 molecules/mole) = 6.022*10^23 molecules
However, each atom of methane includes four atoms of hydrogen, so the number of H atoms is:
(6.022*10^23 molecules) * (4 H atoms/molecule) = 24.088*10^23 atoms
H atoms in 1 mol of CH4 =
1 mol = 6.022*10^23 (Avogadro's number)
(6.022*10^23)CH4/ * 4H/
1 mol CH4
= (6.022*10^23)4
2.408 * 10^24
One molecule has four atoms.So one mole has four moles of Hyrrogen
One molecule has four H atoms.So four moles of H are given
It is 1.2*10^23.
4
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
Take the balanced equation. CH4+2O2---->CO2+2H2O.So two moles are consumed
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
About 1 mole
Molecular formula: CH4 Structural formula: . H H C H . H CH4 (1 carbon and 4 hydrogen) it is NOT ch4 it is CH4; 4 being a subscript indicating 4 hydrogen atoms bonded into a single carbon atom
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
In 3 moles of CH4, there are 18.06 x 10^23 times Hydrogen atoms.
0.86 moles CH4 (4 mole H/1 mole CH4)(6.022 X 10^23/1 mole H) = 2.1 X 10^24 atoms of hydrogen --------------------------------------------
One molecule has four H atoms.So two moles have 8 moles
Take the balanced equation. CH4+2O2---->CO2+2H2O.So two moles are consumed
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
156 grams CH4 (1 mole CH4/16.042 grams) = 9.72 moles of methane ==================
This is the Sabatier process and is usually in need of high temperature and a metallic catalyst. So, balanced equation. CO2 + 4H2 -> CH4 + 2H2O As said, hydrogen is in excess, so CO2 is limiting and drives the reaction. One to one 36.6 moles CO2 (1 mole CH4/1 mole CO2) = 36.6 moles CH4 produced in this reaction -------------------------------------------------------
There are 0.75 moles in it.You have to devide 12 by molecular mass
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
One mole of molecules is equal to 6.02x1023 molecules. There are 4 hydrogen atoms in every molecule of methane (CH4). 6.02x1023 x 4 = 2.41x1024 hydrogen atoms.