1 mole is 6.022*10^23 "things," so 1 mole of CH4 (methane) contains
(1.00 mol) * (6.022*10^23 molecules/mole) = 6.022*10^23 molecules
However, each atom of methane includes four atoms of hydrogen, so the number of H atoms is:
(6.022*10^23 molecules) * (4 H atoms/molecule) = 24.088*10^23 atoms
There are 12 atoms of hydrogen in 3 moles of CH4. CH4 consists of one carbon atom and four hydrogen atoms. Since each mole of CH4 has 4 hydrogen atoms, 3 moles would have 3 * 4 = 12 hydrogen atoms in total.
Take the balanced equation. CH4+2O2---->CO2+2H2O.So two moles are consumed
There are 0.5 moles of hydrogen in 1g, as the molar mass of hydrogen is 2g/mol.
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
There are 12 atoms of hydrogen in 3 moles of CH4. CH4 consists of one carbon atom and four hydrogen atoms. Since each mole of CH4 has 4 hydrogen atoms, 3 moles would have 3 * 4 = 12 hydrogen atoms in total.
There are 24 moles of hydrogen in 4 moles of CH4 because each molecule of CH4 contains 4 hydrogen atoms. Therefore, you have 24 moles x 6.022 x 10^23 atoms/mol = 1.4448 x 10^25 atoms of hydrogen.
One molecule has four H atoms.So two moles have 8 moles
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
In 0.86 moles of CH4, you have 5.16 x 10^23 atoms of hydrogen. This is because there are four hydrogen atoms in one molecule of CH4, making a total of 0.86 x 4 = 3.44 moles of hydrogen atoms, which can be converted to atoms using Avogadro's number.
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
For the reaction CO2 + 4H2 -> CH4 + 2H2O, the stoichiometry shows that 1 mole of CO2 produces 1 mole of CH4. Therefore, 25.1 moles of CO2 would produce 25.1 moles of CH4.
This is the Sabatier process and is usually in need of high temperature and a metallic catalyst. So, balanced equation. CO2 + 4H2 -> CH4 + 2H2O As said, hydrogen is in excess, so CO2 is limiting and drives the reaction. One to one 36.6 moles CO2 (1 mole CH4/1 mole CO2) = 36.6 moles CH4 produced in this reaction -------------------------------------------------------
There are 0.75 moles in it.You have to devide 12 by molecular mass
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
The complete combustion of methane proceeds according to the equation: CH4 + 2 O2 = CO2 + 2 H2O. Therefore, each mole of methane produces two moles of water and 4 moles of methane will produce eight moles of water.