Take the balanced equation. CH4+2O2---->CO2+2H2O.So two moles are consumed
There are five moles.There is one mole of carbon and four moles of hydrogen.
18 moles of oxygen are needed.
1 mole is 6.022*10^23 "things," so 1 mole of CH4 (methane) contains (1.00 mol) * (6.022*10^23 molecules/mole) = 6.022*10^23 molecules However, each atom of methane includes four atoms of hydrogen, so the number of H atoms is: (6.022*10^23 molecules) * (4 H atoms/molecule) = 24.088*10^23 atoms
A mole is a counting unit of molecules. Since sodium is an element and is exists by itself one mole of sodium will equal one mole of atoms or 6.02 x 1023 atoms.
There is one mole of iodine in one mole. There are 126.90447grams of iodine in one mole. There are also 6.022x1023 atoms in one mole.
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
There are 6.022x10^23 atoms in one mole of oxygen, or Avogadro's number.
One molecule has only one C atom.So 0.56mol has 0.56mol of C atoms
One mole of molecules is equal to 6.02x1023 molecules. There are 4 hydrogen atoms in every molecule of methane (CH4). 6.02x1023 x 4 = 2.41x1024 hydrogen atoms.
Each molecule of methane contains one carbon atom, as shown by the formula for methane, CH4. Therefore, the number of carbon atoms in one mole of methane is the same as Avogadro's Number, about 6.022 X 1023.
There five atoms in CH4.One carbon and four Hydrogen.
1 mole is 6.022*10^23 "things," so 1 mole of CH4 (methane) contains (1.00 mol) * (6.022*10^23 molecules/mole) = 6.022*10^23 molecules However, each atom of methane includes four atoms of hydrogen, so the number of H atoms is: (6.022*10^23 molecules) * (4 H atoms/molecule) = 24.088*10^23 atoms
Let us get number atoms of the constituent first.4 grams CH4 (1 mole CH4/16.042 grams)(6.022 X 1023/1 mole CH4)= 1.5 X 1023 atoms of methane========================so,Carbon is one to one in the molecular formula, so let's get the number of hydrogen atoms in this mass methane.1.5 X 1023 atoms CH4 (4 mole H/1 mole CH4)= 6 X 1023 atoms hydrogen======================now, we proceed to find electrons1.5 X 1023 atoms carbon * 6 electrons= 9 X 1023 electrons carbon--------------------------------------6 X 1023 atoms hydrogen * 1 electron= 6 X 1023 electrons hydrogen--------------------------------------------added together= 1.5 X 1024 electrons in 4 grams methane-------------------------------------------------------------( call it 2 X 1024 electrons methane to be in line with significant figures )
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
A mole is a counting unit of molecules. Since sodium is an element and is exists by itself one mole of sodium will equal one mole of atoms or 6.02 x 1023 atoms.
The formula for methane is CH4, showing that each molecule contains exactly 5 atoms. Therefore, the number of atoms in 0.650 ml is 5 X 0.650 X Avogadro's Number, or about 1.96 X 1024 atoms, to the justified number of significant digits.
There are six atoms.Four hydrogen atoms and one carbon atom.
There is one mole of iodine in one mole. There are 126.90447grams of iodine in one mole. There are also 6.022x1023 atoms in one mole.
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