About 1 mole
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
To find the number of moles of hydrogen in 3.5 moles of (NH4)2CO3, first identify the stoichiometry of the compound. In (NH4)2CO3, there are two moles of hydrogen per mole of compound. Therefore, in 3.5 moles of (NH4)2CO3, there would be 2 * 3.5 = 7 moles of hydrogen.
17.32 moles H2O (2 moles H/1 mole H2O) = 34.64 moles hydrogen
To find the number of moles in 12g of hydrogen, we first need to determine the molar mass of hydrogen, which is approximately 1g/mol. Then we can divide the given mass (12g) by the molar mass (1g/mol) to find that there are 12 moles of hydrogen in 12g.
To find the moles of hydrogen, you can divide the given mass of hydrogen by its molar mass. The molar mass of hydrogen is approximately 1 g/mol. So, moles of hydrogen = mass of hydrogen (in grams) / molar mass of hydrogen (approximately 1 g/mol).
To determine the number of moles in 1g of H2SO4, you first need to calculate the molar mass of H2SO4. The molar mass of H2SO4 is approximately 98.08 g/mol. Therefore, 1g of H2SO4 is equal to 0.0102 moles (1g / 98.08 g/mol).
To calculate the number of moles in 1g of ammonia (NH3), you first need to determine the molar mass of ammonia. The molar mass of NH3 is approximately 17 g/mol. Then you can use the formula: number of moles = mass / molar mass. So for 1g of NH3, there would be approximately 0.059 moles present.
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
Seventeen moles of hydrogen correspond to 204,75.10e23 atoms.
In the reaction between 1g of Hydrogen and 19g of Fluorine to form HF, the limiting reactant is Hydrogen. Based on the balanced chemical equation, 1g of Hydrogen will react with 38g of Fluorine to form 2g of HF. In the reaction between 1g of Hydrogen and 80g of Bromine to form HBr, the limiting reactant is Hydrogen. Based on the balanced chemical equation, 1g of Hydrogen will react with 160g of Bromine to form 2g of HBr.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
0,565 moles
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
There are 9.12 moles of hydrogen atoms in 4.56 moles of NH2NH2. Each NH2NH2 molecule contains 2 hydrogen atoms.
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6