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1 mole S = 32.065g
32g S x 1mol/32.065g = 1.0mol S (rounded to 2 significant figures)
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How many atoms are in 25.1 grams in sulfur?
25,1 grams sulfur contain 4,7147765.10e23 atoms.
How many atoms are 6.02 grams of sulfur?
6.02 grams sulfur (1mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.13 X 10^23 atoms sulfur
How many atoms of sulfur are in a 48.0 g chunk of sulfur?
48.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 9.01 X 10^23 atoms of sulfur
Hown many atoms does 32 g of sulfur contain?
32g of Sulfur is a Mole of Sulfur and therefore contains Avogadro's number of atoms of Sulfur. Avogadro's number is 6.023 × 10 to the 23.
How many moles of atoms are there in 48.096 grams of sulfur?
Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------
How many atoms are in 25.1 grams in sulfur?
25,1 grams sulfur contain 4,7147765.10e23 atoms.
How many atoms does g of sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many atoms does 32 g sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many atoms 32 g of sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many sulfur atoms are in 3 grams of sulfur?
1.12875 × 1023
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
How many atoms are 6.02 grams of sulfur?
6.02 grams sulfur (1mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.13 X 10^23 atoms sulfur
How many atoms of sulfur are present in 155 g of sulfur?
93,341,000,000,000,000,000,000,000 or 933.41 x 1023 atoms of arsenic. You just take Avogadro's number (6.022 x 1023) and multiply 6.022 by the number of moles (155) and then multiply the product by 1023.
How many atoms of sulfur are in a 48.0 g chunk of sulfur?
48.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 9.01 X 10^23 atoms of sulfur
How many atoms are there in 72.0 g of sulfur?
72.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.35 X 10^24 atoms of sulfur
Hown many atoms does 32 g of sulfur contain?
32g of Sulfur is a Mole of Sulfur and therefore contains Avogadro's number of atoms of Sulfur. Avogadro's number is 6.023 × 10 to the 23.
How many moles of atoms are there in 48.096 grams of sulfur?
Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------
