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6.02 grams sulfur (1mole S/32.07 grams)(6.022 X 10^23/1 mole S)

= 1.13 X 10^23 atoms sulfur

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Q: How many atoms are 6.02 grams of sulfur?
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In chemestry what does a 'mole' describe?

a mole is a way to express how many particles there are. for example 1 mole of sand consist of 602 250 000 000 000 000 000 000 or 6.0225 × 1023 grains of sand. that's a lot, but if you're talking about atoms that is not so extremely much. for example 1 mole of table salt NaCl is only 58,44grams of salt.why use mole and not grams?I asked myself that same question, but some atoms are heavier then others and you will need more grams of it to have 1 mole, and so you can end up with very complex mathematics while you can just use moles.an other example2H² + O² --> 2H²Othis means that 2moles of hydrogen gas will react with 1 mole of oxygen gas to form 2 moles of water. this is very logical ^^ (for some people).but in grams you need 4 grams of hydrogen 32 grams of oxygen and you will end up with 36grams of water.okay it might sound more logical but look closely and you will see that oxygen gas is much heavier than hydrogen.


What is Avogados' number?

Avogadro's number is a constant that is used in chemistry as means of determining how many atoms/ions/molecules there are in one mole of any substance - element or compound. Despite working in the 1700s, he somehow calculated that this number was (brace yourself): 602, 300, 000, 000, 000, 000, 000, 000. ...or 6.023x1023


Inorganic Chemistry How many moles in 50 grams of NH4 2SO4?

First find out how many grams in 1 mole:Nitrogen is 14.007 g/mol, Hydrogen is 1.0079 g/mol, and Chlorine is 35.453 g/molThere are 4 Hydrogen, so 14.007 + 4*(1.0079) + 35.453 = 53.4916 g/mol(50 g)/(53.4916 g/mol) = 0.9347 moles


How many grams of NaN3 are required to produce 13.0 ft3 of nitrogen gas if the gas has a density of 1.25 gL?

13.0 cubic feet is equivalent to .3681 cubic meters, which is equivalent to 368.1 liters. At 1.25 grams/liter, there are 460.1 grams. Nitrogen gas has a molar mass of 28.0134 g/mol, so there are 16.4 moles of N2. The equation for the decomposition of NaN3 is 2 NaN3 --> 2 Na + 3 N2. So, for every 3 moles of N2, there must have been 2 moles of NaN3, hence there was 10.9 moles. With a molar mass of 65.01 g/mol, there were 709 grams of NaNO3 to begin with.


What is this number 602 000 000 000 000 000 000 000?

602 000 000 000 000 000 000 000 which is Avogadros number. It is the number of particles in one mole of a substance. ex: one mol of Hydrogen is 1.

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