13.0 cubic feet is equivalent to .3681 cubic meters, which is equivalent to 368.1 liters. At 1.25 grams/liter, there are 460.1 grams. Nitrogen gas has a molar mass of 28.0134 g/mol, so there are 16.4 moles of N2. The equation for the decomposition of NaN3 is 2 NaN3 --> 2 Na + 3 N2. So, for every 3 moles of N2, there must have been 2 moles of NaN3, hence there was 10.9 moles. With a molar mass of 65.01 g/mol, there were 709 grams of NaNO3 to begin with.
602 g
63.3 g
2
Yes the number of moles = the number of grams in a given sample / the molecular mass of the substance. Ex. to convert 50 grams of nitrogen to # of moles of nitrogen, you divide 50g by 14.01g (the molecular mass) and you have 3.57 mol Nitrogen
3 grams
8.62
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
Density required for the answer. Subtract volume by density.
Nitrogen is the limiting reactant and 4.15g of ammonia are produced.
63.3 g
2
Yes the number of moles = the number of grams in a given sample / the molecular mass of the substance. Ex. to convert 50 grams of nitrogen to # of moles of nitrogen, you divide 50g by 14.01g (the molecular mass) and you have 3.57 mol Nitrogen
800 g oxygen are needed.
11.5 g NO2
3 grams
16,45 g nitrogen are needed.
8.62